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3 years ago

If the steam in the engine is able to raise a 30 kg piston to a height of 0.68 m, how much work has been done by the steam?

Physics

1 answer:

erica [24]3 years ago

6 0

Answer:

199.92joules

Explanation:

workdone = Mgh

mass x height x acceleration due to gravity

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For which of these questions could a testable hypothesis be developed? Check all that apply. A. Are gases better than solids? B.

Shalnov [3]

Testable hypotheses could be developed for questions <em>B, D, and E</em> .

The main problem with A and C is the word "better". This is a rubber word. It means different things to different people, and it can mean different things to the same person at different times. It's always a matter of opinion, it has no unique units of measure, and there is no concrete way to measure it. Not good for developing a testable hypothesis.

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3 years ago

Read 2 more answers

A 500 kg empty elevator moves with a downwards acceleration of 2 m/s2. What is the tension force of the cable on the elevator? 5

Gre4nikov [31]

Answer:

T = 4000 N

Explanation:

We have,

Mass of an elevator, m = 500 kg

It is moving downward with an acceleration of $2\ m/s^2$ . It is required to find the tension force of the cable on the elevator. We know that when the elevator is moving downward, the net force on it is given by :

$F=m(g-a)$

g is acceleration due to gravity

$F=500\times (10-2)\\\\F=4000\ N$

So, the tension force of the cable on the elevator is 4000 N.

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3 years ago

How does an oxygen concentrator machine work?

zaharov [31]

-It takes air from it's surroundings.
-Compresses the air
-Removes Nitrogen
-Delivers an electric Interface
-Then it delivers the purified oxygen

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3 years ago

A satellite of mass m circles the earth a distance R from the center of the earth.If the radius of the earth is 6.0*10^6ms.calcu

Rom4ik [11]

(a) The height above the earth's surface of the parking orbit is determined from the difference between the orbital radius and earth's radius (h = r - R).

(b) Velocity of the satellite of the earth is determined with a formula given as (2π/T)r.

<h3>Height above the earth's surface </h3>

The height above the earth's surface is calculated using the following formula;

$T = \frac{2\pi r^{\frac{3}{2} }}{\sqrt{Gm} }$

where;

T is time period of the satellite
r is orbital radius

r = h + R

h = r - R

where;

h is height above the earth's surface
R is radius of earth

<h3>Velocity of the satellite</h3>

The velocity of the satellite is determined using the formula below;

v = ωr

v = (2π/T)r

Learn more about velocity of satellite here: brainly.com/question/22247460

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1 year ago

A uniform electric field of magnitude 442 N/C pointing in the positive x-direction acts on an electron, which is initially at re

Brums [2.3K]

A) The electric field is constant and in the same direction as the electron's displacement, so the work done is given by:

W = Fd

W = work, F = electric force, d = displacement

The electric force on the electron is given by:

F = Eq

F = electric force, q = electron charge

Substitute F:

W = Eqd

Given values:

E = 442N/C, q = 1.6×10⁻¹⁹C, d = 3.50×10⁻²m

Plug in and solve for W:

W = 442(1.6×10⁻¹⁹)(3.50×10⁻²)

W = 2.48×10⁻¹⁸J

B) The electric field does work to move the electron. Apply the conservation of energy and you'll see that the electron's potential energy loss is equal to the work done by the field in moving the electron.

The electric potential energy change is -2.48×10⁻¹⁸J

C) Apply the work-energy theorem; the electron's kinetic energy equals the work done on it by the field.

KE = 0.5mv² = W

m = electron mass, v = velocity, W = work

Given values:

W = 2.48×10⁻¹⁸J, m = 9.11×10⁻³¹

Plug in and solve for v:

0.5(9.11×10⁻³¹)v² = 2.48×10⁻¹⁸

v = 2.33×10⁶m/s

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3 years ago