Question

For a body falling freely from rest​ (disregarding air​ resistance), the distance the body falls varies directly as the square of the time. If an object is dropped from the top of a tower 490 ft high and hits the ground in 7 ​sec, how far did it fall in the first 5 ​sec?

Answer 1

Answer:

The answer to the question is

The object would fall 57.625 m in the first 5 seconds

Explanation:

To solve the question, we note that

the height of fall = 490 ft = ‪149.352‬ m

Time to touch the ground = 7 seconds

We are required to find out how far the object falls in the first 5 seconds

We apply the relation

S = u·t + 0.5×g·t ² = We then have

‪149.352‬ = U×7+0.5*9.81*49 From where u = -13 m/s

Therefore to find how far it falls in the first 5 seconds, we have

-13*5 + 0.5*9.81*25 = 57.625 m

Answer 2

Explanation:

Below is an attachment containing the solution.