A lot of windows, skylights, and open floor areas.
A. To find work we need to know F and S; to find power we need to know F and V
Answer:
298,220 N
Explanation:
Let the force on car three is T_23-T_34
Since net force= ma
from newton's second law we have
T_23-T_34 = ma
therefore,
T_23-T_34 = 37000×0.62
T_23= 22940+T_34
now, we need to calculate
T_34
Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2
F= ma
So, F= 12×37000×0.62= 22940×12= 275280 N
T_23 =22940+T_34= 22940+ 275280= 298,220 N
therefore, the tension in the coupling between the second and third cars
= 298,220 N
Answer:
Explanation:
30 km/h b. 60 km/h c. 15 km/h d. 2 km/h. The answer is 15km/h. The rate will be the same. 30km / 2hr = _km / hr. By the law of equivalent fractions ...
Answer:
18 kg/cm³
Explanation:Density=mass/ volume=450/25=18kg/cm³