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lina2011 [118]
3 years ago
13

Two long, parallel wires are separated by a distance of 2.2 cm. The force per unit length that each wire exerts on the other is

3.6 × 10^-5 N/m, and the wires repel each other. The current in one wire is 0.52 A. What is the magnitude of the current in the second wire? (Give your answer in decimal using "A" (Ampere) as unit)
Physics
1 answer:
VikaD [51]3 years ago
5 0

Answer:

i_2 = 7.6 A

Explanation:

As we know that the force per unit length of two parallel current carrying wires is given as

F = \frac{\mu_o i_1 i_2}{2\pi d}

here we know that

F = 3.6 \times 10^{-5} N/m

i_1 = 0.52 A

d = 2.2 cm

now from above equation we have

3.6 \times 10^{-5} = \frac{4\pi \times 10^{-7} (0.52)(i_2)}{2\pi (0.022)}

3.6 \times 10^{-5} = 4.73 \times 10^{-6} i_2

i_2 = 7.6 A

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Answer:

0.2286  m,  0.686 m and  1,143 m

therefore we see that there is respect even where the intensity is minimal

Explanation:

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let's locate the origin on the left speaker

let's find the wavelength with the equation

        v =  λ f

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we substitute

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let's calculate for difference values ​​of n

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we locate the different values ​​for a minimum of interim

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therefore we see that there is respect even where the intensity is minimal

6 0
3 years ago
BRAINLIEST
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Answer:

Explanation:

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Given

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time = 20secs

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average speed = distance/time

Time = distance/speed

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Astronomical unit is mainly used to measure distances within our solar system.

1 AU is equal to  150\times 10^6 km

Thus 160 AU  is equal to \frac{150\times 10^6}{1}\times 160=24000\times 10^6km=24000000000km

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