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Gnesinka [82]
3 years ago
10

Determine how many moles of hydrogen are needed to produce 50 grams of ammonia.

Chemistry
1 answer:
AlladinOne [14]3 years ago
3 0

Answer:

4.41 moles of hydrogen

Explanation:

N2 + 3H2 => 2NH3

No of mole = mass/molar mass

No of mole = 50/17 = 2.94

3 moles of H2 gives 2 moles of ammonia

X moles of H2 gives 2.94 moles of ammonia

X mole of H2 = 3 moles of H2 * 2.94 moles of ammonia/ 2 moles of H2

X = 4.41 moles of hydrogen

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What is the molarity of a solution prepared by dissolving 10.0g of kno3 in 250 ml of solution
maw [93]

Answer:

Mass of KNO3= 10g

Molar mass of KNO3 = 101.1032g/mol

Volume = 250ml = 0.25L

No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3

no of mole of KNO3 = 10/101.1032

No of mole of KNO3 = 0.09891

molarity of KNO3 = no of mole of KNO3/Vol (L)

Molarity = 0.09891/0.25 = 0.3956M

Molarity of KNO3 = 0.3956M

8 0
3 years ago
How many moles of oxygen gas (O2) are required to completely react with 10 moles of hydrogen gas (H2)?
Brums [2.3K]

Answer:

5 moles of oxygen are required.

Explanation:

Given data:

Moles of O₂ required = ?

Moles of H₂ present = 10 mol

Solution:

Chemical equation:

O₂ + 2H₂       →     2H₂O

Now we will compare the moles of oxygen and hydrogen.

                      H₂        :        O₂

                        2         :         1

                       10         :     1/2×10 = 5 mol

5 moles of oxygen are required.

3 0
3 years ago
P-fluoroanisole reacts with sulfur trioxide and sulfuric acid. Draw the major product of this substitution reaction; if applicab
Ipatiy [6.2K]

Answer: (Structure attached).

Explanation:

This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.

The aromatic ring in p-fluoroanisole has two sustituents, an <u>halogen</u> and a <u>methoxy group</u>, which are <em>ortho-para</em> directing substituents.

Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using <u>sulfur trioxide as an electrophile</u> (very reactive).

The reaction occurs in three steps:

  1. The attack on the electrophile forms the sigma complex.
  2. The loss of a proton regenerates an aromatic ring.
  3. The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).

Normally, a mixture of <em>ortho-para</em> substituted products would be obtained. However, since both <em>para</em> positions are occupied, only the <em>ortho </em>substituted product is obtained here.

8 0
3 years ago
Can someone who expert in chemistry be my personal tutor? I'm so desperate​
lions [1.4K]
Yes..? I don’t understand what you’re trying to ask mate.
5 0
3 years ago
Consider separate 1.0-L samples of He(g) and UF6(g), both at 1.00 atm and containing the same number of moles. What ratio of tem
diamong [38]
V =  \sqrt{x} 3 * R * T / MW

V = RMS velocity

R = 8.3145 J/K*mole

T = Temperature K

MW = Molecular weigh in Kg
3 0
3 years ago
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