Answer: Be= 2, C =4, Li = 1 and B=3
Explanation:
The valence shell can be define as the outermost shell of an atom that contains the valence electrons.
Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.
Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.
Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.
Boron (B) , electronic configuration; 1s2 2s2 2p1 = 3 electron in its valence shell.
Answer:
Explanation:
Hello there!
In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:
Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:
Then, we solve for specific heat of the metallic alloy to obtain:
Thereby, we plug in the given data to obtain:
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The Sun, Moon, and stars have helped
people for thousands of years. When you look
into the sky, you will notice that they follow
certain patterns. This happens most of the
time, but not all of the time. Since most
patterns repeat over and over, they have
helped us keep track of time. These patterns
have also helped us make calendars.
Making calendars was a difficult task. Our ancestors had to decide on the length of a year.
Also, they had to decide on the length of a day. As you know a day takes 24
hours. That is the time that Earth takes to rotate once on its axis. A year is longer and
takes 365 days. This length of time is related to the time that it takes for Earth to go
around the Sun. However, this is not exactly true. Earth’s trip takes 365 days – plus a
fraction of another day. This is what complicates our calendar. We have been able to
solve this problem by adding an extra day in the month of February. Most often, you will
see that February has 28 days. Every four years, February has one extra day. During this
year we end up with 29 days in this month. When this happens, the year is called a Leap
Year. It helps us keep our calendar in order.
Deciding on the length of a month has also been a challenge. Some cultures around the
world have used a lunar calendar. A lunar calendar is based on the Moon’s cycle. The
Moon takes 29 and one-half days to complete one cycle. Then things got a lot harder.
Different cultures start their months at a different time of the Moon’s cycle. For example,
the Hebrew and Islamic calendars start their months when a crescent moon is seen in the
sky. The Chinese start their new months at the new moon phase. These differences have
made it harder for cultures to communicate. Trading with one another has also been hard
for this reason.
As time went by, most countries began to use the same calendar. When this happened in
the twentieth century, trade and communication became a lot easier. Some countries
decided to drop thirteen days from their calendar. This is because their old way of
counting did not match up with the new way.
England had problems with the calendar back in the 1500s. The English decided to divide
their calendar into months. Each month had four weeks. By doing this, one week ended
up being longer than seven days. Also, this resulted in thirteen months to a yea
Answer:
Mass is Universal and weight is tied to the strength of the gravitational force of the planet .
Explanation:
The reason is because without mass you have no weight witch means if you have a certain amount of mass you will have a certain weight .
Answer:
d. 103.3
Explanation:
In the given question, the National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. And the units of atmospheric pressure used for reporting the atmospheric pressure data are inches of mercury. For a barometric pressure of 30.51 inches of mercury, we can calculate the pressure in kPa as follow:
In principle, 3.386 kPa is equivalent to the atmospheric pressure of 1 inch of mercury. Thus, 30.51 inches of mercury is equivalent to 30.51 in *(3.386 kPa/1 in) = 103.307 kPa.
Therefore, a barometric pressure of 30.51 inches of mercury corresponds to _____103.3_____ kPa.
