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Gnesinka [82]
3 years ago
10

Determine how many moles of hydrogen are needed to produce 50 grams of ammonia.

Chemistry
1 answer:
AlladinOne [14]3 years ago
3 0

Answer:

4.41 moles of hydrogen

Explanation:

N2 + 3H2 => 2NH3

No of mole = mass/molar mass

No of mole = 50/17 = 2.94

3 moles of H2 gives 2 moles of ammonia

X moles of H2 gives 2.94 moles of ammonia

X mole of H2 = 3 moles of H2 * 2.94 moles of ammonia/ 2 moles of H2

X = 4.41 moles of hydrogen

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Which of the following statements about Ideal Gas Law is supported by Charles's Law?
grin007 [14]

Answer:

B

Explanation:

volume occupied by fixed amount of gas is directly proportional to its absolute temperature.

5 0
3 years ago
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3% Hydrogen Peroxide has an oral LD50 of 900 mg/kg. Acetic Acid has an oral LD50 of 3310 mg/kg. Which one is more hazardous to c
Maurinko [17]
LD50 is defined as the lethal dose 50% which describes the amount of material required to kill 50% of the testing population. It is given in units of mg of chemical per kg of bodyweight of the recipient. 

Comparing hydrogen peroxide and acetic acid, we see that peroxide has a lower LD50 of 900 mg/kg, with acetic acid having LD50 = 3310 mg/kg. When comparing LD50 values, the smaller value will be the more toxic compound. What this means is that in this case, a smaller amount of peroxide is required to kill 50% of the testing population compared to acetic acid.

Therefore, 3% hydrogen peroxide is more hazardous to consume.
7 0
3 years ago
1.2 g of sucrose is added to water with the final volume of 75 ml. What is the concentration of sucrose in %w/v?
Firlakuza [10]

Answer:

16 g/L

Explanation:

Given that:-

Mass of sucrose added = 1.2 g

Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )

%w/v is defined as the mass of the solution in 1 L of the solution.

So,

\%\ w/v=\frac{Mass_{solute}}{Volume_{Solution}}

\%\ w/v=\frac{1.2\ g}{0.075\ L}=16\ g/L

8 0
3 years ago
Why is oxygen an element ? a it is essential to life b it burn c it combines with hydrogen d it cannot be broken down into a sim
MrRa [10]
D.) It cannot be broken down into a simple substance through chemical means...
5 0
3 years ago
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Part complete When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation
nikdorinn [45]

<u>Answer:</u> The isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

<u>Explanation:</u>

Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.

In a nuclear reaction, the total mass and total atomic number remains the same.

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Ba}+^{94}_{36}\textrm{Kr}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 94 + 3

A = 139

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

Z = 56

The isotopic symbol of barium is _{56}^{139}\textrm{Ba}

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Sr}+^{143}_{54}\textrm{Xe}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

A = 90

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

Z = 38

The isotopic symbol of strontium is _{38}^{89}\textrm{Sr}

Hence, the isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

7 0
3 years ago
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