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3 years ago

Determine how many moles of hydrogen are needed to produce 50 grams of ammonia.

Chemistry

1 answer:

AlladinOne [14]3 years ago

3 0

Answer:

4.41 moles of hydrogen

Explanation:

N2 + 3H2 => 2NH3

No of mole = mass/molar mass

No of mole = 50/17 = 2.94

3 moles of H2 gives 2 moles of ammonia

X moles of H2 gives 2.94 moles of ammonia

X mole of H2 = 3 moles of H2 * 2.94 moles of ammonia/ 2 moles of H2

X = 4.41 moles of hydrogen

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What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?

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Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

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Molarity: 1.56 M= 1.56 $\frac{moles}{liter}$
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Replacing:

$1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}$

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

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Ca: 40 g/mole
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Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

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$mass=\frac{4.14 moles*110.9g}{1 mole}$

mass= 459.126 g

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