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sasho [114]
3 years ago
12

How many covalent bonds does oxygen form if each of its unpaired electrons participate in one bond?

Chemistry
2 answers:
ICE Princess25 [194]3 years ago
8 0
The oxygen atom has 4 valence electrons. Valence electrons are the electrons found in the outermost shell of an atom. These are the electrons that participate in chemical reactions during bonding. Since 4 electrons make up 2 pairs, an oxygen atom is capable of making <em>2 covalent bonds</em>.
MrRissso [65]3 years ago
3 0

Oxygen forms two covalent bonds or a single double bond.  

Further explanation:  

Oxygen forms two covalent bonds, or a double covalent bond. It has two unpaired electrons. Oxygen has six electrons in its outermost orbital which are involved in bonding.  

Covalent bond:

A bond which is formed by the mutual sharing of electrons is called a covalent bond. The valence electrons of an atom are involved in the formation of a covalent bond. The covalent bond is of many types depending upon its kinds of bonding atoms or bond order. Oxygen atom containing six electrons in its outermost orbit forms a double covalent bond.  

According to bond order the following are the three types of covalent bonds:

Single covalent bond:

The type of covalent bond which is formed by the mutual sharing of one electron pair is termed as single covalent bond.  

For example:  

The bond in hydrochloric acid is a covalent bond.  

Double covalent bond:

A bond which is formed by the mutual sharing of two pairs of electrons is termed as double covalent bond.  

For example:

Bond in carbon dioxide etc.  

Triple covalent bond:

A bond which is formed by the mutual sharing of three pair of electrons is called a triple covalent bond.  

For example:  

Bond present in acetylene etc.  

Strength of bonds:  

Double covalent bond is stronger than a single covalent bond and a triple covalent bond is stronger than the double covalent bond.  

Answer details

Subject: Chemistry

Level: College

Keywords

  • Covalent bond
  • Single covalent bond
  • Double covalent bond
  • Triple covalent bond
  • Strength of bonds

Learn more to evaluate

brainly.com/question/10885719  

brainly.com/question/5031462

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3 0
3 years ago
Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3
Margarita [4]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

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777dan777 [17]

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Explanation:

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Answer:

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This impacts the diversity of the offspring because it can be an exact copy of the reproducer (Asexual), or significantly different with some similarities if the mode of reproduction was sexual.

I really hope this helps you! Please tell me if it did or not. Good luck with your assignment/exam/quiz!

(OMG TYSM FOR BRAINLIEST!! :D)

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