Answer:
The correct answer is option B.
Explanation:
![3NaOH+2NBr_3\rightarrow 3HOBr+3NaBr+N_2](https://tex.z-dn.net/?f=3NaOH%2B2NBr_3%5Crightarrow%203HOBr%2B3NaBr%2BN_2)
Moles of
= 40 mol
Moles of NaOH = 48 mol
According to reaction, 3 moles of NaOH reacts with 2 moles ![NBr_3](https://tex.z-dn.net/?f=NBr_3)
Then ,48 moles of NaOH will reacts with:
of ![NBr_3](https://tex.z-dn.net/?f=NBr_3)
Then ,40 moles of
will reacts with:
of NaOH
As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.
Moles left after reaction = 40 mol - 32 mol = 8 mol
Hence, the
is an excessive reagent.
Answer:
Perigee
Explanation:
In Perigee, The moon appears closer.
Because mixture composition can combust while put compound you have to be careful and know what you mixing
Answer:
![Q=54.8kJ](https://tex.z-dn.net/?f=Q%3D54.8kJ)
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:
![\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Cfrac%7B46.2kJ%7D%7Bmol%7D%20%2A%5Cfrac%7B1mol%7D%7B3molH_2%7D%5C%5C%5C%5C%20%5CDelta%20H%3D15.4%5Cfrac%7BkJ%7D%7BmolH_2%7D)
Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:
![Q=7.19gH_2*\frac{1molH_2}{2.02gmolH_2}*15.4\frac{kJ}{molH_2} \\\\Q=54.8kJ](https://tex.z-dn.net/?f=Q%3D7.19gH_2%2A%5Cfrac%7B1molH_2%7D%7B2.02gmolH_2%7D%2A15.4%5Cfrac%7BkJ%7D%7BmolH_2%7D%20%5C%5C%5C%5CQ%3D54.8kJ)
Best regards!