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4vir4ik [10]
2 years ago
12

Infrared radiation has a longer wavelength, ____ frequency, and ____ energy than visible light.

Chemistry
2 answers:
vodka [1.7K]2 years ago
5 0
Infrared radiation has a longer wavelength, HIGHER frequency and LOWER energy than visible light.
Hope this helps!!!!!!!
KATRIN_1 [288]2 years ago
4 0

<u>Answer:</u> The correct answer is lower, lower.

<u>Explanation:</u>

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}       .....(1)

where,

E = energy of the light

h = Planck's constant

c = speed of light

\lambda = wavelength of light

We also know that:

\nu=\frac{c}{\lambda}     ......(2)

where,

\nu = frequency of light

From equation 1 and 2, we get that wavelength is inversely proportional to energy as well as frequency of the light. So, if the wavelength of light is high, that means energy and frequency will be low.

Hence, the correct answer is lower, lower.

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The most reactive metals are located in which area of the periodic table?
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The answer is b.Far left
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Which of the following has more energy than visible light?
Svetlanka [38]
It should be radio waves. If you need anymore help look up the wavelength chart online.

6 0
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Melting is an endothermic process. Using the terms 'kinetic energy' and 'intermolecular forces', explain how the addition of ene
Helen [10]

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3 0
3 years ago
Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
Stels [109]
<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
                                            (+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
Or,
                            Au  =  6 / 2

                            Au  = +3
Result:
                            Au  =  +3
                            Se  =  +6
                            O   =  -2

                                                      Ni(CN)₂


Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
                                         Ni + (-1)₂  =  0

                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




6 0
3 years ago
A sample of pure oxalic acid (H2C2O4.2H2O) weighs 0.2000 g and requires 30.12 ml of KOH solution for
ValentinkaMS [17]

 The molarity  of KOH  is  0.1055 M

 <u><em> calculation</em></u>

Step  1: write  the  equation  for reaction between H₂C₂O₄.2H₂O  and KOH

H₂C₂O₄.2H₂O  + 2 KOH   →    K₂C₂O₄ +4 H₂O

step 2: find the moles  of H₂C₂O₄.2H₂O

moles = mass÷ molar  mass

from  periodic  table the  molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4)  + 2(18)=126 g/mol

 = 0.2000 g ÷ 126 g/mol =0.00159  moles


step 3: use the  mole  ratio  to  calculate the moles of KOH

H₂C₂O₄.2H₂O : KOH  is 1:2

therefore the  moles of KOH  =0.00159 x 2 = 0.00318  moles

step 4: find molarity of KOH

molarity = moles/volume in liters

volume in liters = 30.12/1000=0.03012 L

molarity  is therefore = 0.00318/0.03012 =0.1055 M

5 0
3 years ago
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