The metal which will reach the highest temperature is the metal with the lowest specific heat capacity.
<h3>What is the amount of heat added to each metal?</h3>
The amount of heat Q = mcΔT where
- m = mass of metal
- c = specific heat capacity of mateal and
- ΔT = temperature change
<h3>Temperature change of the metal</h3>
Making ΔT subject of the formula, we have
ΔT = Q/mc
Given that Q and m are the same for each metal,
ΔT ∝ 1/c
We see that the temperature change is inversely proportional to the specific heat capacity.
Since the metals are at the same temperature, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.
So, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.
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Answer:
<h2>Heterogeneous</h2>
Explanation:
<h3><em>Milk </em><em>seems</em><em> to</em><em> be</em><em> </em><em>homogeneous</em><em> mixture</em><em> </em><em>but </em><em>actually</em><em> </em><em>milk </em><em>is </em><em>a </em><em>heterogeneous</em><em> </em><em>mixture</em><em> </em><em>and </em><em>a </em><em>colloid</em><em> </em><em>solution</em><em>.</em></h3>
Answer:
pKa = 3.675
Explanation:
∴ <em>C</em> X-281 = 0.079 M
∴ pH = 2.40
let X-281 a weak acid ( HA ):
∴ HA ↔ H+ + A-
⇒ Ka = [H+] * [A-] / [HA]
mass balance:
⇒<em> C</em> HA = 0.079 M = [HA] + [A-]
⇒ [HA] = 0.079 - [A-]
charge balance:
⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water
⇒ [H+] = [A-]
∴ pH = - log [H+] = 2.40
⇒ [H+] = 3.981 E-3 M
replacing in Ka:
⇒ Ka = [H+]² / ( 0.079 - [H+] )
⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )
⇒ Ka = 2.113 E-4
⇒ pKa = - Log ( 2.113 E-4 )
⇒ pKa = 3.675
Answer:
calcium oxide is injected into the final stage of the scubber, wich then reacts with the sulfur dioxide to form calcium sulfite.
Explanation:
Answer:
Given the activity series of elements, the reaction that will occur is: 2AgNO3 + Ni -----> Ni(NO3)2 + 2Ag