Anybody ? Know how to do this

Physics

1 answer:

Nesterboy [21]3 years ago

4 0

Just look at the periodic table and google how to read an element from the periodic table. A picture of a single cell from the table will pop up with arrows of what's what and it will help you answer this in no time! (Brainliest please)

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A 9.0-V battery is connected to a resistor so that there is a 0.50-A current through the resistor.For how long should the batter

salantis [7]

Answer:

35.6 s

Explanation:

The power through the resistor is given by:

$P=VI$

where V=9.0 V is the voltage and I=0.50 A is the current. Substituting into the formula, we find

$P=(9.0 V)(0.5 A)=4.5 W$

The power is also equal to:

$P=\frac{W}{t}$

where W is the work done while t is the time taken. Since we know the work done, W=160 J, we can re-arrange the equation to find the time taken:

$t=\frac{W}{P}=\frac{160 J}{4.5 W}=35.6 s$

7 0

4 years ago

Given the initial wavefunction Ψ (x, 0) = Axexp (-k x) withx> 0 andk> 0, and Ψ (x, 0) = 0 forx <0, what value must A ta

madam [21]

Answer with explanation:

The Normalization Principle states that

$\int_{-\infty }^{+\infty }f(x)dx=1$

Given

$f(x)=xe^{-kx}(x>0\\\\0(x$

Thus solving the integral we get

$\int_{0 }^{+\infty }A\cdot xe^{-kx}dx=1\\\\A\int_{0 }^{+\infty }\cdot xe^{-kx}dx=1$

The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below

$I=\int xe^{-kx}dx\\\\x\int e^{-kx}dx-\int \frac{d(x)}{dx}\int e^{-kx}dx\\\\-\frac{xe^{-kx}}{k}-\int 1\cdot \frac{-e^{-kx}}{k}\\\\\therefore I=\frac{e^{-kx}}{k}-\frac{xe^{-kx}}{k}$