D. 1 1.212.52 -2 12 12

4. A 100-kg soldier in the Arctic is coasting on his ice skates at a speed of 3.0 m/s. He fires 35 bullets directly forward from

FinnZ [79.3K]

Answer:

The gunner must apply 240 N to the gun to stop it from moving back.

Explanation:

6 0

3 years ago

Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile? Answ

Vinil7 [7]

Answer: 272.82 drop/tile

Explanation:

Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?

Tiles/ft^2 × drop/tiles = drop/ft^2

Tiles will cancel out. Leaving the answer to be drop/ ft^2

Substitutes all the magnitude of the above units.

17 × drop/tiles = 4638

Make drop/tiles the subject of formula

Drop/tiles = 4638/17

Drop/tiles = 272.82

Therefore, 272.82 drop/tile drops fall on each tile?

8 0

3 years ago

A 1500 kg car skids to a halt on a wet road where μk = 0.47. You may want to review (Pages 141 - 145) . Part A How fast was the

shusha [124]

The car travels at a speed of 25m/s.

Explanation:

Given-

Mass, m = 1500kg

Coefficient of friction, μk = 0.47

Distance, x = 68m

Speed, s = ?

We know,

$Force, F = ma$

and

F = μ X m X g

Therefore,

μ * m * g = m * a

μ * g = a

Let, g = 9.8m/s²

So,

$a = 0.47 * 9.8 m/s^2$

$a = 4.606m/s^2$

We know,

$v^2 - u^2 = 2as$

where, v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

If the car comes to rest, the final velocity, v becomes 0.

So,

$u^2 = 2 * 4.606 * 68\\\\u^2 = 626.416m/s\\\\u = 25m/s$

The car travels at a speed of 25m/s.

6 0

3 years ago

What are the 3 units we use to measure the universe??

ioda

If you mean what types of measurements are used to measure in outer space, I believe it’s light-year, astronomical unit and intergalactic measurements, but I’m not completely sure.

Hopefully this helps...

6 0

3 years ago

If the thermal energy of the system increases by 400 J, and 1,100 J of heat were added to the system, how much work did the syst

Luba_88 [7]

700 J is the work done by the system.

Explanation:

The first law of thermodynamics is that the change in internal energy of the system is equal to the net heat transfer to the system minus the complete work performed by the system.

$\Delta \boldsymbol{U}=\boldsymbol{Q}-\boldsymbol{W}$

Where,

∆U – Change in internal energy

Q – Heat transfer to the system

Q – Work done

Here,

Given data:

∆U - 400 J

Q - 1100 J

We need to the work done by the system (W)

By applying the given values in the above equation, we get

400 = 1100 - W

W = 1100 - 400 = 700 J

7 0

3 years ago