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svetlana [45]
3 years ago
14

D. 1 1.212.52 -2 12 12

Physics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

what?

Explanation:

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Look at the diagram showing the different wavelengths in sunlight.
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Explanation:

They are infrared waves which mean they take the form of heat.

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Spend time observing or thinking about events that involve matter and energy. Which events can you explain? Which event's can't
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Eating. Your muscles in your arms and mouth use energy to feed itself. Then your body digest the food which also takes energy.

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A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball above the ground t seconds af
natima [27]

Answer:

When the ball hits the ground, its velocity is -128 ft/s.

Explanation:

Hi there!

First, let's find the time it takes the ball to reach the ground (the value of t for which s(t) = 0):

s(t) = -16t² + 32t + 240

0 = -16t² + 32t + 240

Solving the quadratic equation with the quadratic formula:

t = 5.0 s (the other solution of the equation is rejected because it is negative).

Now, we have to find the velocity of the ball at t = 5.0 s.

The velocity of the ball is the change of height over time (the derivative of s(t)):

v = ds/dt = s'(t) = -32t + 32

at t = 5.0 s:

s'(5.0) = -32(5.0) + 32 = -128 ft/s

When the ball hits the ground, its velocity is -128 ft/s.

4 0
3 years ago
How do you select the appropriate tools for caregiving rated task effectively?​
Gwar [14]

Answer:

Care giving tools like medical devices or any medical supplies which aid the effectiveness of care for the patient will help the quality of work of care giving. ... All of the care giving tool should also be efficient and effective

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A 5.7 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 4.5 + 13.7 x − 1.5 x 2 , where
const2013 [10]

Answer:

The work done by the force on the particle is 29.85 J.

Explanation:

The work is given by:  

W = ^{x_{2}}_{x_{1}}\int F_{x} dx

Where:

x₁: is the lower limit = 0 m    

x₂: is the upper limit = 1.9 m

Fₓ: is the force in the horizontal direction =  (4.5 + 13.7x - 1.5x²)N

W = ^{1.9}_{0}\int (4.5 + 13.7x - 1.5x^{2}) dx  

W = 4.5x|^{1.9}_{0} + \frac{13.7}{2}x^{2}|^{1.9}_{0} - \frac{1.5}{3}x^{3}|^{1.9}_{0}  

W = 4.5N(1.9 m) + \frac{13.7N}{2}(1.9 m)^{2} - \frac{1.5N}{3}(1.9 m)^{3}    

W = 4.5N(1.9 m) + \frac{13.7N}{2}(1.9 m)^{2} - \frac{1.5N}{3}(1.9 m)^{3}      

W = 29.85 J

Therefore, the work done by the force on the particle is 29.85 J.

I hope it helps you!                                

6 0
3 years ago
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