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3 years ago

1) A parked car starts to move with a constant velocity of 3 m/s, after moving

Physics

1 answer:

makkiz [27]3 years ago

7 0

Answer:

velocity (v) =distance(s) ÷ time (t)

Explanation:

v=s÷t

s=v×t

s=3×3.4

s= 10.2m

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3 years ago

Shrill sound is of -------------- *

Leona [35]

Answer:

Higher frequency.

Explanation:

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3 years ago

A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio

tatuchka [14]

Answer:

acceleration = 0.2625 m/s²

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using the equation:

acceleration = ( 10.6 - 6.4 ) / 16

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6 0

3 years ago

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Which of the following forms matter?<br> A. Proteins<br> B.atoms<br> C.cells<br> D. DNA

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Answer:b) atoms

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3 years ago

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A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm

Mashutka [201]

Answer:

$a = 0.53 m/s^2$

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

$\omega = 2\pi f$

$\omega = 2\pi ( \frac{20}{60})$

$\omega = 2.10 rad/s$

so final tangential speed is given as

$v = r\omega$

$v = 1.71 (2.10) = 3.58 m/s$

now average acceleration of the girl is given as

$a = \frac{v_f - v_i}{\Delta t}$

$a = \frac{3.58 - 0}{6.73}$

$a = 0.53 m/s^2$

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3 years ago