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Sauron [17]
3 years ago
6

Which type of wave is not a light wave

Physics
1 answer:
AlekseyPX3 years ago
4 0

<em><u>A</u></em><em><u>. </u></em><em><u>R</u></em><em><u>E</u></em><em><u>D</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u>S</u></em><em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>L</u></em><em><u>I</u></em><em><u>G</u></em><em><u>H</u></em><em><u>T</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>C</u></em><em><u>A</u></em><em><u>U</u></em><em><u>S</u></em><em><u>E</u></em><em><u> </u></em><em><u>THE</u></em>RE<em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u> </u></em><em><u>RED</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u>.</u></em>

<em><u>A</u></em><em><u>L</u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>F</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u> </u></em><em><u>D</u></em><em><u>O</u></em><em><u>N</u></em><em><u>T</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>E</u></em><em><u>A</u></em><em><u>R</u></em><em><u>C</u></em><em><u>H</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>F</u></em><em><u>R</u></em><em><u>O</u></em><em><u>M</u></em><em><u> </u></em><em><u>G</u></em><em><u>O</u></em><em><u>O</u></em><em><u>G</u></em><em><u>L</u></em><em><u>E</u></em>

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Climates on Earth get _____ as you move from the equator to the poles.
andreev551 [17]
The correct answer that would best complete the given statement above would be the last option: COLDER. Climates on Earth get colder <span>as you move from the equator to the poles. The places that are located near or on the equator experience the warmest or the hottest climates such as Africa. Hope this answer helps. </span>
5 0
3 years ago
Read 2 more answers
The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.4cm apart with a 28kV potential d
yulyashka [42]

Answer:

a)   F = 3.2 10⁻¹⁰ N , b)       v = 9.9 10⁷ m / s

Explanation:

a) The electric force is

       F = q E

The electric field is related to the potential reference

     V = E d

     E = V / d

Let's replace

    F = e V / d

Let's calculate

    F = 1.6 10⁻¹⁹ 28 10³ / 1.4 10⁻²

    F = 3.2 10⁻¹⁰ N

b) For this part we can use kinematics

          v² = v₀ + 2 a d

          v = √ 2 ad

Acceleration can be found with Newton's second law

        e V / d = m a

        a = e / m V / d

        a = 1.6 10⁻¹⁹ / 9.1 10⁻³¹ 28 10³ / 1.4 10⁻²

        a = 3,516 10⁻¹⁷ m / s²

Let's calculate the speed

       v = √ (2 3,516 10¹⁷ 1.4 10⁻²)

       v = √ (98,448 10¹⁴)

       v = 9.9 10⁷ m / s

3 0
2 years ago
How are the amplitude and energy of a wave related
In-s [12.5K]
I would go with the last two because they are the same  please give me brainiest if i am right

<span />
3 0
2 years ago
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if vector u has lenght 70 and direction 40 degrees, and vector v has length 85 and direction 335 degrees what is the length and
Anastaziya [24]

Answer:

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

Explanation:

||u|| = 70

θ = 40°

\vec{u}_x=||u||cos\theta \\\Rightarrow \vec{u}_x=70cos40=53.62

\vec{u}_y=||u||sin\theta \\\Rightarrow \vec{u}_y=70sin40=44.99

||v|| = 85

θ = 335°

\vec{v}_x=||v||cos\theta \\\Rightarrow \vec{v}_x=85cos335=77.03

\vec{v}_y=||v||sin\theta \\\Rightarrow \vec{v}_y=85sin335=-35.92

Resultant

R=\sqrt{R_x^2+R_y^2}\\\Rightarrow R=\sqrt{(\vec{u}_x+\vec{v}_x)^2+(\vec{u}_y+\vec{v}_y)^2}\\\Rightarrow R =\sqrt{(70cos40+85cos335)^2+(70sin40+85sin335)^2}\\\Rightarrow R =131.15

\theta=tan^{-1}\frac{R_y}{R_x}\\\Rightarrow \theta=tan^{-1}\frac{70sin40+85sin335}{70cos40+85cos335}\\\Rightarrow \theta=tan^{-1}0.069=3.97^{\circ}

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

4 0
3 years ago
When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end
Sunny_sXe [5.5K]

1) 29.8 C

At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).

2) 6.2 C

The temperature change of the water is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

T_f = 29.8 C\\T_i = 23.6 C

Substituting into the formula,

\Delta T=29.8 C-23.6 C=6.2 C

And the positive sign means that the temperature of the water has increased.

3) -40.6 C

The temperature change of the metal is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

T_f = 29.8 C\\T_i = 70.4 C

Substituting into the formula,

\Delta T=29.8 C-70.4 C=-40.6 C

And the negative sign means the temperature of the metal has decreased.

5 0
3 years ago
Read 2 more answers
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