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cluponka [151]
3 years ago
9

we see a magnet exerting a force on a current-carrying wire. Does a current-carrying wire exert a force on a magnet? Why or why

not?
Physics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

Yes

Explanation: Electric and magnetic field are known to be inter-related, this implies that for any current carrying conductor there is a resulting magnetic field around the wire ( for example a current carrying conductor deflects a compass) and a magnetic field has been known to produce some amount current based on the<em> </em>principle of electromagnetic induction by Micheal Faraday.

The strength of magnetic field generated by a current carrying conductor is given by Bio-Savart law (purely mathematical) which is

B =\frac{u_{0}I }{2πr}

B= strength of magnetic field

I =current on conductor

r = distance on any point of the conductor relative to it center

If a current carrying could generate this magnitude of magnetic field, thus this magnetic field has the ability to interact (exert a force on any magnetic material) with any other magnetic material including a magnet.

Yes, a current carrying conductor can exert a force on a magnetic field

Nady [450]3 years ago
3 0

Answer: Yes

Explanation:

This is because a current carrying wire creates a magnetic field, hence if a current carrying wire is placed in a magnetic field, the wire would experience a force which would be exerted by magnetic field. Flemings left hand rule can be used to find the direction of the force exerted by the conductor. Using your left hand, if the forefinger, second finger and thumb are placed at right angles to one another and provided that the forefinger represent the direction of the field, the second finger represent the current, then the thumbs gives the direction of the force.

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Shawn uses 45 N of force to stop the cart 27 meter from running his foot over. How much work does he do?
Ede4ka [16]

Answer:

W=f×d

w=45×27

w=1215 j.............

3 0
3 years ago
A jogger hears a car alarm and decides to investigate. While running toward the car, she hears an alarm frequency of 872.10 Hz.
Nata [24]

Answer:

v = 4.18 m/s

Explanation:

given,

frequency of the alarm = 872.10 Hz

after passing car frequency she hear = 851.10 Hz

Speed of sound = 343 m/s

speed of the jogger = ?

speed of the

v_f = \dfrac{872.10-851.10}{2}

v_f =10.5\ Hz

v_o = 872.1 - 10.5

V_0 = 861.6\ Hz

The speed of jogger

v = \dfrac{v_1 \times 343}{v_0}-343

v = \dfrac{872.1 \times 343}{861.6}-343

v = 4.18 m/s

5 0
3 years ago
Vector ~A has a negative x-component 3.07 units in length and a positive y-component 3.17 units in length. When a vector ~B = b1
luda_lava [24]

Answer:

a. 3.07 b. 1.26

Explanation:

Given that A = -3.07i + 3.17j and B = b1i + b1j and C = A + B = 0i + 4.43j

Since A + B = -3.07i + 3.17j + b1i + b2j

= (-3.07 + b1)i + (3.17 + b2)j

So,(-3.07 + b1)i + (3.17 + b2)j = 0i + 4.43j

Comparing components,

-3.07 + b1 = 0 (1) and 3.17 + b2 = 4.43 (2)

a. From (1), b1 = 3.07

b. From(2) b2 = 4.43 - 3.17 = 1.26

4 0
2 years ago
A Porsche challenges a Honda to a 400 m race. Because the Porsche's acceleration of 3.4 m/s2 is larger than the Honda's 3.0 m/s2
padilas [110]

Answer:

Winner wins by 0.969 s

Explanation:

For the Porche:

Given:

Displacement of Porsche s = 400 m

Acceleration of Porsche a = 3.4 m/s^2

From Newton's second equation of motion,

s = ut + (1/2) a t^2 (u = 0 as the car was initially at rest)

Substituting the values into the equation, we have

t^2 = (2 * 400) / 3.4

= 235.29 / 3.4

t = 15.33 s

For the Honda:

Displacement of Honda = 310 m

Acceleration of Honda = 3 m/s^2

Applying Newton's second equation of motion

s = ut + (1/2) a t^2 (u = 0 for same reason)

Substituting the values into the equation, we obtain

t^2 = (2 * 310) / 3

= 620 / 3

t = 14.37 s

Hence

The winner (honda) wins by a time interval of = 15.33 - 14.37    

=0.969 s

8 0
3 years ago
Which of Newton’s Laws involves mass and acceleration? Question 1 options: 3rd 1st 2nd All of them
Feliz [49]
The answer would be Newton’s Second Law
6 0
3 years ago
Read 2 more answers
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