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cluponka [151]
3 years ago
9

we see a magnet exerting a force on a current-carrying wire. Does a current-carrying wire exert a force on a magnet? Why or why

not?
Physics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

Yes

Explanation: Electric and magnetic field are known to be inter-related, this implies that for any current carrying conductor there is a resulting magnetic field around the wire ( for example a current carrying conductor deflects a compass) and a magnetic field has been known to produce some amount current based on the<em> </em>principle of electromagnetic induction by Micheal Faraday.

The strength of magnetic field generated by a current carrying conductor is given by Bio-Savart law (purely mathematical) which is

B =\frac{u_{0}I }{2πr}

B= strength of magnetic field

I =current on conductor

r = distance on any point of the conductor relative to it center

If a current carrying could generate this magnitude of magnetic field, thus this magnetic field has the ability to interact (exert a force on any magnetic material) with any other magnetic material including a magnet.

Yes, a current carrying conductor can exert a force on a magnetic field

Nady [450]3 years ago
3 0

Answer: Yes

Explanation:

This is because a current carrying wire creates a magnetic field, hence if a current carrying wire is placed in a magnetic field, the wire would experience a force which would be exerted by magnetic field. Flemings left hand rule can be used to find the direction of the force exerted by the conductor. Using your left hand, if the forefinger, second finger and thumb are placed at right angles to one another and provided that the forefinger represent the direction of the field, the second finger represent the current, then the thumbs gives the direction of the force.

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A man whose mass is 69 kg and a woman whose mass is 52 kg sit at opposite ends of a canoe 5 m long, whose mass is 20 kg. Suppose
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Answer:

the canoe moved 1.2234 m in the water

Explanation:

Given that;

A man whose mass = 69 kg

A woman whose mass = 52 kg

at opposite ends of a canoe 5 m long, whose mass is 20 kg

now let;

x1 = position of the man

x2 = position of canoe

x3 = position of the woman

Now,

Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3

= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20

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Centre of mass is 2.19858 m

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52 × 2.5 / ( 69 + 52 + 20 )

= 130 / 141

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To get how far, the canoe moved;

⇒ 2.5 + 0.9219858 - 2.19858

= 1.2234 m

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