The short answer is "it is a very intense star."
Acceleration = (change in speed) / (time for the change)
Change in speed = (speed after the change) - (speed before the change)
Change in speed = (65 m/s) - (35 m/s) = 30 m/s
Acceleration = (30 m/s) / (5 s)
<em>Acceleration = 6 m/s²</em>
v₀ = initial velocity of the mobile = 10 m/s
v = final velocity of the mobile = 20 m/s
a = acceleration of the mobile = 5 m/s²
d = distance traveled during this operation = ?
Using the kinematics equation
v² = v²₀ + 2 a d
inserting the above values in the equation
20² = 10² + 2 (5) d
400 = 100 + 10 d
subtracting 100 both side
400 - 100 = 100 - 100 + 10 d
300 = 10 d
dividing both side by 10
300/10 = 10 d/10
d = 30 m
hence mobile travels 30 m.
Answer:
20.96 m/s
Explanation:
Apply the kinematic equation:
Vf=Vi+at
Vi=8m/s
a=1.8m/s^2
t=7.2s
Putting this all in should give you your answer of 12.96m/s
Answer:
% differ 1.72%
Explanation:
given data:
P_ideal = 13.51 atm
n = 1.074 mol
V = 1.746 L
T = 267.6 K
According to ideal gas law we have
(P+0.514)(1.711) = 23.59
P_v = 13.276 atm
% differ
= 1.72%