we see a magnet exerting a force on a current-carrying wire. Does a current-carrying wire exert a force on a magnet? Why or why
2 answers:
Answer:
Yes
Explanation: Electric and magnetic field are known to be inter-related, this implies that for any current carrying conductor there is a resulting magnetic field around the wire ( for example a current carrying conductor deflects a compass) and a magnetic field has been known to produce some amount current based on the<em> </em>principle of electromagnetic induction by Micheal Faraday.
The strength of magnetic field generated by a current carrying conductor is given by Bio-Savart law (purely mathematical) which is
B =
B= strength of magnetic field
I =current on conductor
r = distance on any point of the conductor relative to it center
If a current carrying could generate this magnitude of magnetic field, thus this magnetic field has the ability to interact (exert a force on any magnetic material) with any other magnetic material including a magnet.
Yes, a current carrying conductor can exert a force on a magnetic field
You might be interested in
Answer:
Explanation:
given,
r = 539 m
v = 32 m/s
road banked at = 5°
∑ F_x
∑ F_y = 0
=
components of the speed of the coin is given as
now the time taken by the coin to reach the plate is given by
now in order to find the height
so it is placed at 1.52 m height
Answer:
(a). The tension in the cable is 658.33 N.
(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.
(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.
Explanation:
Given that,
Weight of beam= 190 N
Here, The center of gravity is at its center
According to figure,
The angle is
The horizontal component is
The vertical component is
(a). We need to calculate the tension in the cable
Using formula of net torque acting on the pivot
Put the value into the formula
(b). We need to calculate the horizontal components of the force exerted on the beam at the wall
Using formula of horizontal component
Put the value into the formula
(c). We need to calculate the vertical components of the force exerted on the beam at the wall
Using formula of vertical component
Put the value into the formula
Hence, (a). The tension in the cable is 658.33 N.
(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.
(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.
