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Neko [114]
2 years ago
12

Suppose that a tiny space invader (m=0.47 kg) and the new space station orbit Earth at the same height from Earth’s surface. Whi

ch one has a greater orbital speed?
Physics
1 answer:
Ad libitum [116K]2 years ago
6 0

The tiny space invader and the new space station will have equal orbital speed.

<h3>The orbital speed of satellite </h3>

The orbital speed of satellite on Earth surface is given as;

V = \sqrt{\frac{GM}{r} }

where;

  • V is the orbital speed
  • G is universal gravitation
  • M is mass of the Earth
  • r is the radius of the circular path

Since the two objects are at the same height from Earth's surface, the distance from the central point (r) will be the same. Thus, the two objects will have equal orbital speed.

Learn more about orbital speed here: brainly.com/question/22247460

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A 100 kg marble slab falls off a skyscraper and falls 200 m to the ground without hitting anyone. Its fall stops within millisec
Radda [10]

Answer:

Δ T = 2.28°C

Explanation:

given,

mass of marble = 100 Kg

height of fall = 200 m

acceleration due to gravity = 9.8 m/s²

C_marble = 860 J/(kg °C)

using conservation of energy

Potential energy = heat energy

  m g h = m C_{marble}\Delta T

  g h =C_{marble}\Delta T

  \Delta T= \dfrac{g h}{C_{marble}}

  \Delta T= \dfrac{9.8 \times 200}{860}

        Δ T = 2.28°C

7 0
3 years ago
A high speed train is traveling at a speed of 44.7 m/s when the engineer sounds the 415 Hz warning horn. The speed of sound is 3
il63 [147K]

Answer:

Explanation:

Speed of the source of sound = v = 44.7 m/s

Speed of sound = V = 343 m/s

a) Apparent  frequency as the train approaches = f =  [V /(V -v) ] × f

= [343 / (343 - 44.7) ] × 415  = 477.18 Hz

Wave length =  λ = v / f = 343 / 477.18 = 0.719 m

b) Frequency heard as the train leaves = f ' =  [V / ( V + v) ] f

                                                                     = [343 / { 343 + 44.7 ) ] x 415

                                                                      = 367.2 Hz

Wavelength when leaving = v / f = 343 / 367.2 = 0.934 m

8 0
3 years ago
A 4.00-kg block is attached to a vertical rod by means of two strings. when the system rotates about the axis of the rod, the st
Alina [70]
Https://answers.yahoo.com/question/index?qid=20130908151723AA4vGjO

3 0
3 years ago
What is the best reason for having a strong hypothesis?
Elena-2011 [213]

Answer:

the answer is C

Explanation:

i did this

7 0
2 years ago
Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan
elena55 [62]

Answer:

10.07m/s^2

Explanation:

Information we have:

velocities:

initial velocity: v_{i}=0mph (starts from rest)

final velocity: v_{f}=50mph

time:  t=2.22s

Since we need the answer in m/s^2, we nees to convert the speed to meters per second:

v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s

We find the acceleration with the following formula:

a=\frac{v_{f}-v_{i}}{t}

substituting the known values:

a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2

the acceleration is 10.07m/s^2

8 0
2 years ago
Read 2 more answers
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