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Nataly_w [17]
3 years ago
9

contrast longitudinal and transverse waves by describing the particle movement in sound and water waves :​

Chemistry
1 answer:
Airida [17]3 years ago
3 0

Answer: In a transverse wave, the particles of the medium move perpendicular to the wave's direction of travel. Transverse waves are characterized by peaks and valleys, called crests and troughs. In a longitudinal wave, the particles of the medium move parallel to the wave's direction of travel.

Explanation:

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A skateboarder coasts a distance of 20 meters in 4 seconds. What is the person's speed?
yKpoI14uk [10]

Answer:

5

Explanation:

20/4

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How are plant cells different from animal cells?
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b.

They can convert the sun's energy into food.

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A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1". KOH + Cu(NO3)2 → KNO
svet-max [94.6K]

2KOH + Cu(NO3)2 → 2KNO3 + Cu(OH)2

2K⁺ 1Cu²⁺ 2K⁺ 1Cu²⁺

2OH ⁻ 2NO3⁻ 2NO3⁻ 2OH⁻

5 0
3 years ago
A first-order reaction has a half-life of 29.2 s . how long does it take for the concentration of the reactant in the reaction t
Dmitriy789 [7]

Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value

<span> The half-life for the chemical reaction is 29,2 s and is independent of initial concentration.
c</span>₀ - initial concentration the reactant.

c - concentration of the reactant remaining at time.

t = 29,2 s.<span>
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s</span> = 0,0237 1/s.<span>
ln(c/c</span>₀) = -k·t₁.<span>
ln(1/16 </span>÷ 1) = -0,0237 1/s · t₁.

t₁ = 116,8 s.

5 0
4 years ago
Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
Kipish [7]

Answer:

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

Moles of NaOH = \frac{15.0 g}{40 g/mol}=0.375 mol

Molarity of the nitric acid solution = 0.250 M

Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

Molarity=\frac{Moles}{Volume(L)}

n=0.250 M\times 0.150 L=0.0375 mol

NaOH+HNO_3\rightarrow NaNO_3+H_2O

According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

\frac{1}{1}\times 0.0375 mol of NaOH

Moles of NaOH left unreacted  in the solution =

= 0.375 mol - 0.0375 mol = 0.3375 mol

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

Then 0.3375 moles of NaOH will give :

1\times 0.3375 moles=0.3375 mol of hydroxide ion

The molarity of hydroxide ion in solution ;

=\frac{0.3375 mol}{0.150 L}=2.25 M

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

3 0
3 years ago
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