1 year ago

*10) A horizontal force of 7N is pushing an object to the left and a second force of

Physics

1 answer:

antiseptic1488 [7]1 year ago

3 0

∑Fx = (-7) + (12 cos 30⁰) =

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When she rides her bike, she gets to her first classroom building 36 minutes faster than when she walks. Of her average walking

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Answer:

$d=2.4\ miles$

Explanation:

Given:

average walking speed, $v_w=3\ mph$

average biking speed, $v_b=12\ mph$

<u>According to given condition:</u>

$t_w=t_b+\frac{36}{60}$

where:

$t_w=$ time taken to reach the building by walking

$t_b=$ time taken to reach the building by biking

We know that,

$\rm time=\frac{distance}{speed}$

so,

$\frac{d}{v_w} =\frac{d}{v_b} +\frac{36}{60}$

$\frac{d}{3}=\frac{d}{12} +\frac{3}{5}$

$d=2.4\ miles$

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What is the relationship in which the ratio of the manipulated variable and the responding variable is constant? A. inverse prop

Dafna1 [17]

That's a direct proportion.

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An object travels 20 m in 10s What is its speed?

ella [17]

speed=distance/time

distance=20m

time=10s

speed=?

speed=20×10

speed=200m/s

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2 years ago

Ixchelt burns her tongue when she takes a sip of hot coffee from her mug. Which part of this example represents heat?

bekas [8.4K]

Answer:

Explanation:

"The thermal energy moving from her coffee to the tongue" represent the heat.

Here coffee is at high temperature while tongue is at low temperature, when Ixchelt tongue make contact with coffee then thermal energy of coffee is absorbed by tongue and tongue gets burned.

As heat always from high Potential to low that is why heat is absorbed by tongue.

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Which pair of equations can describe the path of a particle moving with an acceleration that is perpendicular to the velocity of

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Answer:

The question clearly describes the circular motion.

The circular motion equation is

$a_{radial} = \frac{v^2}{r}$

The path of the particle is circular.

Explanation:

In circular motion, the radial acceleration is always towards the center and constant in magnitude. Furthermore, the velocity of the circular motion is always tangential to the circle, that is it is always perpendicular to the radius, hence the acceleration.

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