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Nookie1986 [14]
4 years ago
14

A student does an experiment with a pendulum. In the first trial, she displaces the pendulum 5 cm. In the second trial, she disp

laces the same pendulum a distance of 10 cm.
In what ways would the graphs that represent these simple harmonic motion graphs be different? In what ways would they be the same?
Physics
2 answers:
notka56 [123]4 years ago
7 0
<span>The displacement of the pendulum is directly proportional to the amplitude of the sine wave produced. The period would not change because the length of the pendulum rod remains the same.</span>
Y_Kistochka [10]4 years ago
6 0

Answer:

The graphs that represent the displacement would be different, while the graphs that represent the period would be the same

Explanation:

The displacement of the two pendulums is different. In fact, in the first trial the amplitude of the oscillation of the pendulum is 5 cm, while in the second trial the amplitude of the oscillation is 10 cm. Since the displacement is given by the equation

x(t)=A sin(\omega t)

where A is the amplitude, we see that the displacement x(t) of the two trials will be different.

On the contrary, the period of oscillation in the two trials will be the same. In fact, the period of a pendulum is given by

T=2 \pi \sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the acceleration due to gravity. we see that the period depends only on the length of the pendulum, L, so since the same pendulum is used in the two trials, we can conclude that the period will be the same.

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Two tuning forks, 492 Hz and 498 Hz, are struck simultaneously. How many beats will be heard?
Ket [755]

Answer:

6 beats

If one fork beats once and another twice in the same time period

you would hear 1 beat. (Same for 2 and 3 beats).

5 0
3 years ago
A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
Elenna [48]

The tension in the cable is 23.2 N

<h3>What is the tension in the string?</h3>

The tension in the cable can be resolved into horizontal and vertical forces Tcosθ and Tsinθ respectively.

Tcosθ, is acting perpendicularly, Tcosθ = 0

Taking moments about the pivot:

Tsinθ * 2.2 = 4 * 9.8 * 0.7

Solving for θ;

θ = tan⁻¹(1.4/2.2) = 32.5°

T = 27.44/(sin 32.5 * 2.2)

T = 23.2 N

In conclusion, the tension in the cable is determined by taking moments about the pivot.

Learn more about moments of forces at: brainly.com/question/23826701

#SPJ1

3 0
2 years ago
A skier moving at 4.75 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220
disa [49]
First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force, \mu m g. For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
ma=-\mu m g
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
a=-(0.220)(9.81 m/s^2)=-2.16 m/s^2

Now we can use the following relationship to find the distance covered by the skier before stopping, S:
2aS=v_f^2-v_i^2
where v_f=0 is the final speed of the skier and v_i=4.75 m/s is the initial speed. Substituting numbers, we find:
S=- \frac{v_i^2}{2a}=- \frac{(4.75 m/s)^2}{2(-2.16 m/s^2)}=5.23 m
5 0
3 years ago
How high can a 40 N force move a load, when 395 J of work is done?
Juliette [100K]

Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

7 0
3 years ago
A force of 0.2 Newtons is required to slide a book across the table. The book accelerates at 0.11 m/s squared. What is the mass
adelina 88 [10]
My calculations state, not rounding, the mass is 1.8
3 0
3 years ago
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