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Nookie1986 [14]
3 years ago
14

A student does an experiment with a pendulum. In the first trial, she displaces the pendulum 5 cm. In the second trial, she disp

laces the same pendulum a distance of 10 cm.
In what ways would the graphs that represent these simple harmonic motion graphs be different? In what ways would they be the same?
Physics
2 answers:
notka56 [123]3 years ago
7 0
<span>The displacement of the pendulum is directly proportional to the amplitude of the sine wave produced. The period would not change because the length of the pendulum rod remains the same.</span>
Y_Kistochka [10]3 years ago
6 0

Answer:

The graphs that represent the displacement would be different, while the graphs that represent the period would be the same

Explanation:

The displacement of the two pendulums is different. In fact, in the first trial the amplitude of the oscillation of the pendulum is 5 cm, while in the second trial the amplitude of the oscillation is 10 cm. Since the displacement is given by the equation

x(t)=A sin(\omega t)

where A is the amplitude, we see that the displacement x(t) of the two trials will be different.

On the contrary, the period of oscillation in the two trials will be the same. In fact, the period of a pendulum is given by

T=2 \pi \sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the acceleration due to gravity. we see that the period depends only on the length of the pendulum, L, so since the same pendulum is used in the two trials, we can conclude that the period will be the same.

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Blood pressure is usually measured by wrapping a closed air-filled jacket equipped with a pressure gage around the upper arm of
Sever21 [200]

Answer:

a) High and low pressures are 15.999 kilopascals and 10.666 kilopascals, respectively.

b) High and low pressures are 2.320 pounds per square inch and 1.547 pounds persquare inch, respectively.

c) High and low pressures are 1.632 meters water column and 1.088 meters water column, respectively.

Explanation:

a) <em>High and low pressures in kilopascals</em>:

101.325 kPa equals 760 mm Hg, then, we can obtain the values by a single conversion:

p_{high} = 120\,mm\,Hg\times \frac{101.325\,kPa}{760\,mm\,Hg}

p_{high} = 15.999\,kPa

p_{low} = 80\,mm\,Hg\times \frac{101.325\,kPa}{760\,mm\,Hg}

p_{low} = 10.666\,kPa

High and low pressures are 15.999 kilopascals and 10.666 kilopascals, respectively.

b) <em>High and low pressures in pounds per square inch</em>:

14.696 psi equals 760 mm Hg, then, we can obtain the values by a single conversion:

p_{high} = 120\,mm\,Hg\times \frac{14.696\,psi}{760\,mm\,Hg}

p_{high} = 2.320\,psi

p_{low} = 80\,mm\,Hg\times\frac{14.696\,psi}{760\,mm\,Hg}

p_{low} = 1.547\,psi

High and low pressures are 2.320 pounds per square inch and 1.547 pounds persquare inch, respectively.

c) <em>High and low pressures in meter water column in meters water column</em>:

We can calculate the equivalent water column of a mercury column by the following relation:

\frac{h_{w}}{h_{Hg}} = \frac{\rho_{Hg}}{\rho_{w}}

h_{w} = \frac{\rho_{Hg}}{\rho_{w}}\times h_{Hg} (Eq. 1)

Where:

\rho_{w}, \rho_{Hg} - Densities of water and mercury, measured in kilograms per cubic meter.

h_{w}, h_{Hg} - Heights of water and mercury columns, measured in meters.

If we know that \rho_{w} = 1000\,\frac{kg}{m^{3}}, \rho_{Hg} = 13600\,\frac{kg}{m^{3}}, h_{Hg, high} = 0.120\,m and h_{Hg, low} = 0.080\,m, then we get that:

h_{w, high} = \frac{13600\,\frac{kg}{m^{3}} }{1000\,\frac{kg}{m^{3}} } \times 0.120\,m

h_{w, high} = 1.632\,m

h_{w, low} = \frac{13600\,\frac{kg}{m^{3}} }{1000\,\frac{kg}{m^{3}} } \times 0.080\,m

h_{w, low} = 1.088\,m

High and low pressures are 1.632 meters water column and 1.088 meters water column, respectively.

4 0
3 years ago
If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?
yaroslaw [1]

Answer:

735watts

Explanation:

Power = Force*distance/time

Given

Force = mg = 50 * 9.8'

Force = 490N

distance = 3m

time = 2s

Substitute

Power = 490*3/2

Power = 1470/2

Power = 735Watts

Hence the minimum power output is 735watts

7 0
3 years ago
Derive the expression for the equivalent resistance of three resistors in[1] paraleli [2] series
sergeinik [125]
The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.

When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.
8 0
3 years ago
Please , physics. A and B
stepladder [879]

Answer:

a. -5,4

b. 28

Explanation:

(see how to solve in pic)

7 0
3 years ago
Suppose you have two magnets. Magnet A doesn't have its poles labeled, but Magnet B does have a clearly labeled north and south
Elina [12.6K]

Before going to answer this question first we have to know the fundamental principle of magnetism.

A magnet have two poles .The important characteristic of a magnet is that like poles will repel each other while unlike poles will attract each other.

Through this concept the question can be answered  as explained below-

A-As per first option the side of  magnet A is repelled by the south pole  of magnet B. Hence the pole of a must be south .It can't be north as it will lead to attraction.

B-The side of magnet A is repelled by the  north pole of magnet B. Hence the side of A must be  north pole.It can't be a south pole.

C-The side of magnet A is attracted by the south pole  of magnet  B .Hence the side of magnet A must be north.Hence this is right

D-The side of magnet A is attracted by the north pole of magnet B. Hence the side of A must south.It can't be north as it will lead to repulsion.

Hence the option C is right.

3 0
3 years ago
Read 2 more answers
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