2 years ago

How much force is required to accelerate a 50 kg mass at 2 m/s

Physics

1 answer:

marta [7]2 years ago

3 0

Answer:

F = 100 Newtons

Explanation:

F = ma

F = (50 kg)(2 m/s)

F = 100 kg*m/s

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Answer:

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3 years ago

A person is standing on a scale in an unmoving elevator. The elevator starts to move upwards at 1 m/s squared. Is the scale read

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HENCE

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2 years ago

a car initially at 65.00 m/s accelerates at 22.39 m/s^2. How far has the car traveled before it comes to a stop

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94.35 meter

Step by step explanation

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2 years ago

A typical wall outlet voltage is 120 volts in the United States. Personal MP3 players require much smaller voltages, typically 2

butalik [34]

Answer:

Number of turns in secondary will be 7

Explanation:

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Number of turns in the primary is $N_p=3575$

Secondary voltage is given $V_s=235mV=0.235volt$

We have to find the number of turns in secondary

We know that $\frac{N_p}{N_s}=\frac{V_p}{V_s}$

So $\frac{3575}{N_s}=\frac{120}{0.235}$

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As the number of turns can not be in decimal so number of turns will be 7

6 0

3 years ago

A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire), Fig. 5–39.

Trava [24]

Answer:

1742.24106 revolutions per day

Explanation:

v = Velocity

d = Diameter = 1.1 km

r = Radius = $\dfrac{d}{2}=\dfrac{1.1}{2}=0.55\ km$

g = Acceleration due to gravity = 9.81 m/s²

g = 0.9 g

The centrifugal force will balance the gravitational force

$F_c=mg\\\Rightarrow \dfrac{mv^2}{r}=m0.9g\\\Rightarrow v=\sqrt{\dfrac{0.9gmr}{m}}\\\Rightarrow v=\sqrt{0.9gr}\\\Rightarrow v=\sqrt{0.9\times 9.81\times 0.55\times 10^3}\\\Rightarrow v=69.68464\ m/s$

$\dfrac{1}{T}=\dfrac{v}{2\pi r}\\\Rightarrow \dfrac{1}{T}=\dfrac{69.68464}{2\pi 0.55\times 10^3}\times 24\times 60\times 60\\\Rightarrow \dfrac{1}{T}=1742.24106\ rev/day$

The rotation speed is 1742.24106 revolutions per day

6 0

3 years ago

Read 2 more answers