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Leviafan [203]
2 years ago
9

How much force is required to accelerate a 50 kg mass at 2 m/s

Physics
1 answer:
marta [7]2 years ago
3 0

Answer:

F = 100 Newtons

Explanation:

F = ma

F = (50 kg)(2 m/s)

F = 100 kg*m/s

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A loop of area 0.100 m² is oriented at a 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0 degree
MatroZZZ [7]

The resulting change in the magnetic flux is =0.013Wb

what is magnetic flux?

Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. It provides the measurement of the total magnetic field that passes through a given surface area

Given:

At degree =15.5°,magnetic flux=magnetic field=0.500T

At degree=45.0°, magnetic field=0.500T

Magnetic flux=magnetic field ×Area×cos(angle)

magnetic flux (1) = 0.500×0.1×cos(15.5)

= 0.048

magnetic flux (2) = 0.500×0.1×cos(45)

=0.035

Resulting change in flux = 0.048-0.035

= 0.013Wb

learn more about magnetic flux from here: brainly.com/question/28179515

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8 0
2 years ago
a painting in an art gallery has height h and is hung so that its lower edge is a distance d above the eye of an observer. How f
harkovskaia [24]

Solution:

With reference to Fig. 1

Let 'x' be the distance from the wall

Then for \DeltaDAC:

tan\theta = \frac{d}{x}

⇒ \theta = tan^{-1} \frac{d}{x}

Now for the \DeltaBAC:

tan\theta = \frac{d + h}{x}

⇒ \theta = tan^{-1} \frac{d + h}{x}

Now, differentiating w.r.t x:

\frac{d\theta }{dx} = \frac{d}{dx}[tan^{-1} \frac{d + h}{x} -  tan^{-1} \frac{d}{x}]

For maximum angle, \frac{d\theta }{dx} = 0

Now,

0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} -  tan^{-1} \frac{d}{x}][/tex]

0 = \frac{-(d + h)}{(d + h)^{2} + x^{2}} -\frac{-d}{x^{2} + d^{2}}

\frac{-(d + h)}{(d + h)^{2} + x^{2}} = \frac{{d}{x^{2} + d^{2}}

After solving the above eqn, we get

x = \sqrt{\frac{d}{d + h}}

The observer should stand at a distance equal to x = \sqrt{\frac{d}{d + h}}

4 0
3 years ago
A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circu
lana [24]

Answer:

0.500 T

Explanation:

Since the change in time and the number of coils are both 1, I set the problem up to be 1.3=(1.5(x)-13(x)). I then plugged in numbers for x until I got the answer to be 1.3 V.

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Three small children of mas 20.0 kg, 24.0 kg, and 16.0 kg, respectively, hold hands, as
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