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Svetach [21]
3 years ago
11

Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound

intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 29 cm.
What is the wavelength of the sound?

If the distance between the speakers continues to increase, at what separation will the sound intensity again be a maximum?
Express your answer using two significant figures.
Physics
1 answer:
Roman55 [17]3 years ago
6 0

Answer:

a.96cm

b.77cm

Explanation:

Highest intensity,d_1=19cm

Lowest intensity,d_2=29cm

d_1+d_2=19+29=48cm  

48cm is the distance for half-wave, wavelength =48cm*2=96cm

b. From a, above we know that half-wavelength is 48cm

Also, the distance of known  maximum is 29cm

Next maximum is calculated as:

Next \m\aximum=Last \ Maximum+ \ 0.5Wavelength\\=29cm+48cm\\=77cm

The next maximum will occur at 77cm

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Answer:

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Explanation:

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If the police car is a stationary observer, the frequency is:

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fL = frequecy police car receives

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1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

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