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Answer:
h(x) ≤ 5
Step-by-step explanation:
The function and boundaries given are;
h(x) = x + 2, x < 3
And ;
h(x) = -x + 8, x ≥ 3
Now,in the first condition, the maximum value of x will be 2. This means the maximum value of h(x) there is;
h(2) = 2 + 2 = 4
For the second condition, x ≥ 3. Thus, the maximum value of x is 3.
This means that the maximum value of h(x) here is;
h(3) = -3 + 8 = 5
Foe the 2 conditions combined it is clear that the maximum value of h(x) is 5.
Thus,we can say; h(x) ≤ 5
Answer:
Step-by-step explanation:The solution is x > 3
Answer:
Step-by-step explanation:
- x^2+8x-7<0
- x^2 + 8x + 16 - 23 < 0
- (x + 4)^2 < 23
- |x + 4| < √23 ≈ 4.8
1 .
2.
<u>Combination of the two intervals:</u>
Answer:
+- 1/4,1/2,1,2,4
5 solutions.
Step-by-step explanation:
so first we have to do this using the theorum we find all the divors of -2
so +-2, +-1/ +-2,+-1,+-4 so there would be 5 solutions.
+- 1/4,1/2,1,2,4
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