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3 years ago

12

Your skeleton. It is there for support, protection, and movement. But you could not move your bones without the help of your ___

___________ system. A) digestive B) gland C) immune D) muscular\

2 answers:

lana66690 [7]3 years ago

7 0

I believe the answer is D.) the muscular system

Tamiku [17]3 years ago

4 0

The answer would be
D) muscular

You might be interested in

A spherical helium filled balloon (B) with a hanging passenger cage being held by a single vertical cable (C) attached to Earth

Gre4nikov [31]

Answer:

The tension is $T = 4326.7 \ N$

Explanation:

From the question we are told that

The total mass is $m = 200 \ kg$

The radius is $r = 5 \ m$

The density of air is $\rho_a = 1.225 \ kg/m^3$

Generally the upward force acting on the balloon is mathematically represented as

$F_N = T + mg$

=> $(\rho_a * V * g ) = T + mg$

=> $T = (\rho_a * V * g ) - mg$

Here V is the volume of the spherical helium filled balloon which is mathematically represented as

$V = \frac{4}{3} * \pi r^3$

=> $V = \frac{4}{3} * 3.142 *(5)^3$

=> $V = 523.67\ m^3$

So

$T = (1.225 * 523.67* 9.8 ) - 200 * 9.8$

$T = 4326.7 \ N$

5 0

3 years ago

You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 76.2 kg hop on board for a ride

marin [14]

a) The spring constant is 12,103 N/m

b) The mass of the trailer 2,678 kg

c) The frequency of oscillation is 0.478 Hz

d) The time taken for 10 oscillations is 20.9 s

Explanation:

a)

When the two children jumps on board of the trailer, the two springs compresses by a certain amount

$\Delta x = 6.17 cm = 0.0617 m$

Since the system is then in equilibrium, the restoring force of the two-spring system must be equal to the weight of the children, so we can write:

$2mg = k'\Delta x$ (1)

where

m = 76.2 kg is the mass of each children

$g=9.8 m/s^2$ is the acceleration of gravity

$k'$ is the equivalent spring constant of the 2-spring system

For two springs in parallel each with constant k,

$k'=k+k=2k$

Substituting into (1) and solving for k, we find:

$2mg=2k\Delta x\\k=\frac{mg}{\Delta x}=\frac{(76.2)(9.8)}{0.0617}=12,103 N/m$

b)

The period of the oscillating system is given by

$T=2\pi \sqrt{\frac{m}{k'}}$

where

And for the system in the problem, we know that

T = 2.09 s is the period of oscillation

m is the mass of the trailer

$k'=2k=2(12,103)=24,206 N/m$ is the equivalent spring constant of the system

Solving the equation for m, we find the mass of the trailer:

$m=(\frac{T}{2\pi})^2 k'=(\frac{2.09}{2\pi})^2 (24,206)=2,678 kg$

c)

The frequency of oscillation of a spring-mass system is equal to the reciprocal of the period, therefore:

$f=\frac{1}{T}$

where

f is the frequency

T is the period

In this problem, we have

T = 2.09 s is the period

Therefore, the frequency of oscillation is

$f=\frac{1}{2.09}=0.478 Hz$

d)

The period of the system is

T = 2.09 s

And this time is the time it takes for the trailer to complete one oscillation.

In this case, we want to find the time it takes for the trailer to complete 10 oscillations (bouncing up and down 10 times). Therefore, the time taken will be the period of oscillation multiplied by 10.

Therefore, the time needed for 10 oscillations is:

$t=10T=10(2.09)=20.9 s$

#LearnwithBrainly

7 0

3 years ago

Calculate the answer to the correct

oee [108]

Use Star Code: Sebee

5 0

2 years ago

A 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 170 m from top to bottom. at the bottom,

Ainat [17]

I believe this question ask for the energy dissipated by friction.

The overall energy equation for this is:

F = PE – KE

where F is friction loss, PE is potential energy = m g h, KE is kinetic energy = 0.5 m v^2

<span>F = 66 kg * 9.8 m/s^2 * 170 m – 0.5 * 66 kg * (11 m/s)^2</span>

<span>F = 105,963 J ~ 106,000 J </span>

7 0

3 years ago

Read 2 more answers

1. In Bohr's model of the atom, where are the electrons and protons located? (1 point)

r-ruslan [8.4K]

Well, it's really dangerous to try and visualize physical models for things
of this size. But if you must, then it's something like this:

-- The nucleus is a tight-packed bunch of protons and neutrons, located
at the center of each atom.

-- The electrons live all around the nucleus, in a space far from it.
A description of the relative sizes that I read more than 60 years ago
and always stuck with me goes like this: The nucleus in the middle
and the electrons whizzing around it have a size-relationship that's
about the same as a bunch of grapes in the middle of the state of Texas.

This also tells us that matter is mostly empty space !

-- In Bohr's model of the atom, he described the whole thing very much
like a miniature solar system ... the electrons are tiny, solid little balls,
orbiting the nucleus like planets around the sun.

We learned later that it's impossible to talk about things like "how big is
the electron" or "where is the electron" or "how much momentum does
the electron have". The best we can do is talk about a 'cloud' around the
nucleus ... it has some mass and some negative charge, and portions
of it somehow exist at different levels of energy, and can jump to
different levels.

This is NOT because we don't have good enough technology yet to
zoom in on the electrons, and at some time in the future we'll be able
to sharply see where they are and how fast they're moving. It's because
on the scale of atomic dimensions, there is NO SUCH THING as "where
is it" or "how big is it" or "how fast is it moving". These don't exist.
"Location" is described in terms of probability, objects behave like solid
waves, and an object can have this much energy or that much energy
but NO AMOUNT OF ENERGY IN BETWEEN.
Weird ? Hard to understand ? You said it !

BTW ... the answer to the question is ' A ' .

5 0

3 years ago