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aliina [53]
3 years ago
10

What atmospheric conditions can cause sound wave refractions similar to those observed in the ocean?

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
It has to do with we're the water is coming from and we're it's at like city or town
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Hope this helps!
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The universe is made up of __________.
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Explain two scenarios where a large truck can have the same momentum as a small car.
KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0
3 years ago
What makes a tennis ball bounce???? I need to know for my this for my review of literature for my science fair project!!!
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3 years ago
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A cylinder containing an ideal gas has a volume of 2.6 m3 and a pressure of 1.5 × 105 Pa at a temperature of 300 K. The cylinder
frozen [14]
<h2>Answer:13.5\times 10^{8} joules</h2>

Explanation:

From the first law of thermodynamics,

ΔQ=ΔU+W

Where Q is the heat given to the gas,

U is the internal energy of the gas,

W is the workdone by the gas.

When pressure is constant,

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}

When pressure is constant,W=PΔV

Where P is pressure and V is the volume of the gas.

Given P=1.5\times 10^{5}Pa

ΔV=7.8-2.6=5.2m^{3}

So,W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J

Given that ΔU=6\times 10^{5}

So,ΔQ=6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J

5 0
4 years ago
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