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3 years ago

What atmospheric conditions can cause sound wave refractions similar to those observed in the ocean?

Physics

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

It has to do with we're the water is coming from and we're it's at like city or town

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1. True or False: Most things in motion are accelerating, few things in real life move at a constant speed.

lord [1]

1. False
2. Positive
I’m just joking I don’t know the answersss

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3 years ago

Two infinite plane sheets with uniform surface charge densities are placed parallel to each other with separation d. in the regi

kupik [55]

Answer:Uniform between the plates

Explanation:

Electric Field due to infinite sheet with uniform charge is given by

$E=\dfrac{\sigma }{\epsilon _0}$

Where $\sigma$ =charge density

$\epsilon _0$ =Space Permittivity

From the formula we can see that Electric field is independent of distance of the particle, so it is uniform between the plates .

3 0

3 years ago

What is the closeness of measured value to an accepted value?

kotykmax [81]

Accuracy?

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3 years ago

One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large

Eva8 [605]

Answer:

6666.67 Newtons

Explanation:

The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.

In this case:

mass= 0.1mg= 1*10^-7 kg
velocity= 4.00*10^3 m/s
time= 6.00*10^-8 s

Using velocity and time, acceleration can be calculated as:

a= 6.667*10^10 m/s²

Substituting these values into the formula F=ma, the answer is:

F= (1*10^-7)kg * (6.667*10^10) m/s²
F= 6666.67 Newtons of force

5 0

3 years ago

Help quick physics area question

zlopas [31]

Answer: The area of brick in contact with the floor is 1539 $cm^{3}$ .

Explanation:

Given: Length = 19 cm

Width = 9 cm

Height = 9 cm

As the brick is rectangular in shape. Hence, its area will be calculated as follows.

$Area = length \times width \times height$

Substitute the values into above formula as follows.

$Area = length \times width \times height\\= 19 cm \times 9 cm \times 9 cm\\= 1539 cm^{3}$

Thus, we can conclude that area of brick in contact with the floor is 1539 $cm^{3}$ .

8 0

2 years ago