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3 years ago

Explain why hydrogen and oxygen are considered elements whereas water is not considered an element.

2 answers:

5 0

Elements are the simplest building blocks you can break matter down into using purely chemical methods. They are a pure substance made up from only one type of atom.

When you mix elements together these form compounds. The important difference is that as they are a mixture of more than one type of element, they CAN be broken down into more simple substances using chemical means!

As such Hydrogen or Oxygen cannot be simplified chemically (they are therefore elements), however dihydrogen monoxide (H2O or water) is a mixture of these elements that can be broken down using chemical means and so is a compound.

scoundrel [369]3 years ago

3 0

Water is a type of compound . when two elements combine with each other ( hydrogen &oxygen) they forms a compound

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Look at the model below. Which formula is best represented by this model?

Olenka [21]

The third answer because there are two of each atom

6 0

2 years ago

Which of the following mixtures may be act as a buffer solution?

lions [1.4K]

Answer:

B) HF, NaF

Explanation:

A buffer solution is made up of a weak acid and its conjugate base.
In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF, and NaF would make a perfect buffer solution.
The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.

4 0

3 years ago

A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample

-BARSIC- [3]

Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) = 1 dm

Observed rotation (∝) = + 0.27°

Molarity = 0.175 M

Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

Concentration in (g/mL) = 23.275 g/L

Since 1 L = 1000 mL

Concentration in (g/mL) = 0.023275 g/mL

The specific rotation [∝] = ∝/(1×c)

= 0.27°/( 1 dm × 0.023275 g/mL )

= 11.60° mL/g dm

Thus, the specific rotation of D is 11.60° mL/g dm

3 0

3 years ago

At a certain temperature, the solubility of n2 gas in water at 3.08 atm is 72.5 mg of n2 gas/100 g water . calculate the solubil

8090 [49]

According to Henry's law, solubility of solution is directly proportional to partial pressure thus,

$\frac{S_{1}}{P_{1}}=\frac{S_{2}}{P_{2}}$

Solubility at pressure 3.08 atm is 72.5/100, solubility at pressure 8 atm should be calculated.

Putting the values in equation:

$\frac{0.725}{3.08}=\frac{S_{2}}{8}$

On rearranging,

$S_{2}=\frac{0.725\times 8}{3.08}=1.88$

Therefore, solubility will be 1.88 mg of $N_{2}$ gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.

3 0

2 years ago

These are elements that

agasfer [191]

Answer:

metals are those element that have luster,malleable, ductile good conductors of heat and électricity, must have high melting and boiling points, and lose electrons in chemical reactions.

6 0

2 years ago