Answer:
Mass of solute = 0.0036 g
Explanation:
Given data:
Concentration of Cl⁻ = 15.0 ppm
Volume of water = 240 mL
Mass of Cl⁻ present = ?
Solution:
1 mL = 1 g
240 mL = 240 g
Formula:
ppm = mass of solute / mass of sample ×1,000,000
by putting values,
15.0 ppm = (mass of solute / 240 g) ×1,000,000
Mass of solute = 15.0 ppm × 240 g / 1,000,000
Mass of solute = 0.0036 g
Pressure, volume, temperature, # moles Pressure, volume and temperature, and moles of gas
Hope that helps!!!!
Answer:
The answer to your question is: % error = 0.4
Explanation:
Data
real value = 22.48%
estimated value = 22.57 %
Formula
% error = |real value - estimated value|/real value x 100
%error = |22.48 - 22.57|/22.48 x 100
% error = |-0.09|/22.48 x 100
%error = 0.09/22.48 x 100
% error = 0.004 x 100
% error = 0.4
Answer:
44.9g
Explanation:
You have to convert grams of CH4 to moles, use the mole-to-mole ratio of CH4 to water, and convert back to grams.
(20.0g CH4)(1 mol CH4/16.04g)(2 mol H2O/1 mol CH4)(18.01 g H2O/ 1 mol) = 44.9127 g
Hope this helps!
Answer:
This is not plagiarism
Explanation:
Plagiarism maybe defined as the practice or process of copying or imitating another person's concept or idea or writing and pretending that these are their own work. It involves violating the copyright laws.
In the given context, the given student version of paragraph is not plagiarism as words are different from the original writing. And the bibliography reference as well as the citation are correct.
Hence the student version of writing is not a plagiarism.
