Answer:
2.857 × 10⁻⁴ M
Explanation:
First, we will calculate the molarity of the solution 1.
M = mass of solute / molar mass of solute × liters of solution
M = 0.5028 g / 879.9 g/mol × 0.100 L
M = 5.714 × 10⁻³ M
We can find the concentration of the final solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁ / V₂
C₂ = 5.714 × 10⁻³ M × 5 mL / 100 mL
C₂ = 2.857 × 10⁻⁴ M
To solve this question, you must use the formula: q=mc(change in temperature), where q is heat, m is mass, C is specific heat and temperature change is temperature change. The specific heat for ice is 2.1kJ/Kg x K (given). The change in temperature is 15 degrees Celsius (which you should change to kelvins so you can cancel out units), or 273 + 15 = 288K. The mass is 150 grams, which is 0.15 kg. Now, we can solve for q, heat. We will do this by substituting variables into the formula. After simplifying and cancelling out units, the answer we get is: 90.72kJ.
Answer:
The wax
Explanation:
The limiting reactant is the reactant in short supply in a particular reaction. This reactant determines the extent of the reaction. Oxygen in the reaction is the one in excess. As we know that oxygen is free in the atmosphere and it is in excess supply.
After the wax finishes burning the reaction stops and no more production of carbon dioxide, water and energy but oxygen still continues to abound all around.
In order to determine the amount of carbon dioxide and water that would be produce, we simply use the amount of wax to relate with them.
