Help!!! chemistry electrolysis
1 answer:
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Explanation:
The given data is as follows.
Q = 620 C, t = 0.510 hour
First, we will convert hours into seconds. Since, there are 3600 seconds present in 1 hour. Hence, number of seconds present in 0.510 hour are as follows.
= 1836 sec
Therefore, we will calculate the average current as follows.
I =
=
= 0.337 C/sec
It is known that,
1 C/sec = 1000 mA
So,
= 337 mA
Thus, we can conclude that the average current in milliamperes is 337 mA.
Let's start off with the balanced chemical equation:
Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.
Since you have the required mass of NaCl, convert this to moles.
Assuming you know how to find the molar mass of NaCl:
Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:
Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:
Hope this helps :)
Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.
Since you have the required mass of NaCl, convert this to moles.
Assuming you know how to find the molar mass of NaCl:
Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:
Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:
Hope this helps :)