Answer:
Step-by-step explanation:
Given is a function as 
Equating to 0 we have equation
If the function f(x) has x intercepts then the solutions are real
Let us use remainder theorem and change of signs rule
f(0) = 1>0
f(-1) = -1+3+1=3
f(-2) = -32+6+1<0
This implies there is a real root between -1 and -2.
f(1) = -1
Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.
f(2) = 32-6+1>0
Since f(1) and f(2) have different signs there exists a real root between 1 and 2.
Thus there are definitely three real solutions as
one between -1 and 0, one between 0 and 1, and third between 1 and 2.
Volume of the cone: 1/3 of area of the circle * the height
(1/3)π5²*5=(125/3)π
volume of the cylinder: area of the circle *the height: π5²*10=250π
add up: (125/3)π+(125/3)π+250π≈1047.2
D is the correct answer
I think is d correct answer 60%
Answer:
Step-by-step explanation: