How much pure water must mixed with 8 pints of 50 developer to produce a mixture that is 24%?

1 answer:

6 0

8:24 = 0.333(3) pints is one percent
0.333(3)* 100=33.333(3) pints will be 24% mixture with the water
33.3333-8=25.333 pints of water is required for producing 24% mixture

25.3333 pints of pure water and 8 pints of juce.

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Since, Ca is +2 and O is -2, the oxidation number of S could easily be calculated for the given compound as:

Let's say the oxidation number of S in $CaSO_4$ is $x$ . Let's make the algebraic equation and solve it.