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SOVA2 [1]
3 years ago
10

Complete the steps to determine how many triangles ABC can exist with the given measures. b = 18.7, c = 16.1 and C = 35° What is

the approximate value of the height, h, of the triangle? Round to the nearest tenth.
Mathematics
2 answers:
miv72 [106K]3 years ago
4 0

Answer:

............................10.7 :)

Step-by-step explanation:

just took the test

miskamm [114]3 years ago
3 0

Answer:

135.870

Step-by-step explanation:

b=18.7:

c=16.1

C=35 degrees

\frac{16.1}sin35} =\frac{18.7}{sinB} \\sin B =0.4938\\B=29.5

Hence angle A=180-29,5-35

=115.5

Area of a triangle =\frac{1}{2} bcsinA\\=135.870

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Three fair coins are tossed. If all land "heads," the player wins $10, and if exactly two land heads, the player wins $5. If it
hodyreva [135]

Answer:

<u>After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:</u>

<u>1/8 or 12.5% of landing three "heads"</u>

<u>3/8 or 37.5% of landing two "heads"</u>

<u>4/8 or 50% of landing no or only one "head".</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2.  What is the player's expected outcome after four games?

Probability of two coins out of three lands "heads" = 3/8

Probability of three coins out of three lands "heads" = 1/8

Now, let's calculate the player's expected outcome, as follows:

Four games:

Cost = 4 * 4 = $ 16

Worst-case scenario: No wins

Best-case scenario: 4 out of 4 of $ 10 win

Worst-case scenario profit or loss = 0 - 16 = Loss of $ 16

Best-case scenario profit or loss = 40 - 16 = Profit of $ 24

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

8 0
3 years ago
Solving a word problem using a two-step med
stepladder [879]

Inequality is 6t  ≤ 44 and Jim can rent a boat for 7.33 hrs or less

<u> Solution:</u>

Given that  

Maximum amount Jim can spend to rent a boat = $34

Rental cost of boat for 1 hour = $6

Also Jim has a discount coupon for $8 off.

Need to determine possible number of hours Jim could rent a boat.

Let’s assume possible number of hours Jim could rent a boat be represented by variable "t"

Cost of renting boat for 1 hour = 6

So Cost of renting a boat for t hours = t x renting boat for 1 hour = t x 6 = 6t

Also Maximum amount Jim can spend to rent a boat = $34

As Jim has a discount coupon for $8 off, so Total amount Jim can spend to rent a boat = $ 34 + $ 8 = $ 44

So cost of renting a boat for t hours must be less that of equal to Total amount Jim can spend to rent a boat

=> 6t  ≤ 44

On solving above equality for "t" we get ,

\begin{array}{l}{t \leq \frac{44}{6}} \\\\ {=>\mathrm{t} \leq 7.3333 \mathrm{hrs}}\end{array}

Hence inequality is  6t  ≤ 44 and Jim can rent a boat for 7.33 hrs or less.

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On average 43 min an
stealth61 [152]

Answer:

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Step-by-step explanation:

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