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34kurt
3 years ago
10

A box of granola bars contains 3 chocolate chip bars, 2 peanut butter bars, 1 lemon bar, and 4 raisin bars. Iesha will randomly

select a granola bar from the box and then select another bar. What is the probability that the first bar Iesha selects will be lemon and the second will be raisin?
Mathematics
1 answer:
ella [17]3 years ago
3 0

Answer:

2/45

Step-by-step explanation:

Note this selection is done without replacement hence after each selection sample size will reduce

Given data

Samples 3 chocolate chip bars,

2 peanut butter bars,

1 lemon bar, and

4 raisin bars

Sample size S= [3+2+1+4]= 10

Probability that first selection is lemon = 1/10

Probability that second selection is raisin = 4/9

Hence the probability that the first bar Iesha selects will be lemon and the second will be raisin= 1/10*4/9

= 4/90= 2/45

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Maru [420]

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8 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
PLEASE HELP MEH!!! Will give brainliest!
soldier1979 [14.2K]
Petri dish A has 1080000000000000
Petri dish B has 270000000000
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Hope that helped :)

3 0
3 years ago
Read 2 more answers
8 kg of mixed nuts containing 26% peanuts were mixed with 5 kg of another kind of mixed nuts that contain 52% peanuts. peanuts a
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Answer:

<em>36%</em>

Step-by-step explanation:

"8 kg of mixed nuts containing 26% peanuts"

weight of peanuts: 26% * 8 kg = 0.26 * 8 kg = 2.08 kg

"5 kg ... that contain 52% peanuts"

weight of peanuts: 52% * 5 kg = 0.52 * 5 kg = 2.6 kg

Total weight of peanuts: 2.08 kg + 2.6 kg = 4.68 kg

Total weight of mixed nuts: 8 kg + 5 kg

percent of peanuts: (4.68 kg)/(13 kg) * 100% = 36%

6 0
3 years ago
What is the value of 4C9 ?
vekshin1
The answer is 0

The formula is

n!/ r!(n-r)!

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2 years ago
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