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Ahat [919]
3 years ago
9

How do you do C and B

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
"the argument" of a function, is simply "the expression being evaluated by that function".

\bf a)\qquad (x+2)^3\impliedby \stackrel{function}{(\qquad )^3}\qquad \stackrel{argument}{x+2}
\\\\\\
b)\qquad f(2x-1)\impliedby \stackrel{function}{f(\qquad )}\qquad \stackrel{argument}{2x-1}
\\\\\\
c)\qquad \sqrt{x^2+4}\qquad \stackrel{function}{\sqrt{\qquad }}\qquad \stackrel{argument}{x^2+4}
\\\\\\
d)\qquad sin(5x)\impliedby \stackrel{function}{sin(\qquad )}\qquad \stackrel{argument}{5x}
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If f(x) = 4x-9, evaluate f(3) <br>I need HELP ASAP!!!!!!!!!!!​
seropon [69]

Answer:

substitute 3 as in x:

4(3)-9

= 12-9

= 3

Hope this helped - have a nice day & be safe

8 0
3 years ago
K - 4.8=0.32 - 5.4k answer?
RSB [31]

Answer:

k =4/5

Step-by-step explanation:

k - 4.8=0.32 - 5.4k\\\mathrm{Multiply\:both\:sides\:by\:}100\\k\times\:100-4.8\times\:100=0.32\times\:100-5.4k\times\:100\\\\Refine\\100k-480=32-540k\\\\Add\: 480\mathrm{\:to\:both\:sides}\\100k-480+480=32-540k+480\\\\Simplify\\100k=-540k+512\\\\\mathrm{Add\:}540k\mathrm{\:to\:both\:sides}\\100k+540k=-540k+512+540k\\\\Simplify\\640k=512\\\\\mathrm{Divide\:both\:sides\:by\:}640\\\frac{640k}{640}=\frac{512}{640}\\\\k=\frac{4}{5}

5 0
3 years ago
???????????????????????????????????????????
shusha [124]
For question 1, just plug in -2 as <em>h.

</em>-2(-2)^2-(-2)+2
<em>
</em>You would get...

h(-2)=-4
<em>
</em>Hope this helped! <em>-4, or option 1, is correct!</em><em>
</em>
4 0
3 years ago
4x + 6 = 8x – 10 graphing
DIA [1.3K]
Are you graphing or trying to find the answer
8 0
3 years ago
Read 2 more answers
Help plzzz!! Find the slope through these pairs of points
Colt1911 [192]
We can use the formula y2-y1/x2-x1 to find the slope.

1. 2-(-15)/12-5 gives us 17/7. The slope is 17/7.

2. -5-(-20)/6-(-18) gives us 15/24. We can simplify this to 5/8. The slope is 5/8.

3. -19-(-19)/-17-(-18) is 0/1. The slope is 0.

4. -17-3/-11-(-1) is -20/-10. The slope is 2.
8 0
2 years ago
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