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Len [333]
4 years ago
14

The half reaction of an oxidation-reduction reaction shows that iron gains electrons. What does this electron gain mean for iron

? A. It is neutralized. B. It is oxidized. C. It is reduced. D. It has dissolved. E. It has precipitated.
Chemistry
2 answers:
mixas84 [53]4 years ago
8 0

Answer: is C. It is reduced.

Explanation:

Scilla [17]4 years ago
5 0

The  electron  gain  for iron means  that it   is reduced  (answer C)


Explanation

 Redox    reaction  is  made up of two halves.

That  is a   reduction  half and a  oxidization  half.

In the   reduction   half   electrons are  gained  which result  to  decrease  in oxidation number.

In  the Oxidization  half   electrons are  lost which result  to  increase  in  oxidation  number.

iron    is therefore   reduced  since  it gains  electrons


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A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther
sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )

1. Calculate the thermometer readings after  0.5 min and 1 min

(a) After 0.5 min

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}

(b) After 1 min

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

  t = t - 1, because the cooling starts 1 min late

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}

3. Plot the temperature readings as a function of time.

The graphs are shown below.

6 0
3 years ago
Nevermind i got it dont need help thanks
OverLord2011 [107]

Answer:

Ok then...

Explanation:

4 0
3 years ago
State what happens to the potential energy of a the substance during the interval BC *
Ratling [72]

Answer:

The potential energy decreases whereas the kinetic energy increases.

6 0
3 years ago
A sample of H2 gas (2.0 L) at 3.5 atm was combined with 1.5 L of N2 gas at 2.6 atm pressure at a constant temperature of 25 °C i
Tamiku [17]
For this system, we use Dalton's law of partial pressures where the total pressure of a gas mixture is said to be equal to the sum of the partial pressures of the gases. The partial pressure of each gas would be calculated by the product of the mole fraction and the original pressure of the gas. We do as follows:

Total pressure = x1P1 + x2P2
Total pressure = (2.0 / 7.0 )(3.5) + (1.5/7.0)(2.6)
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4 0
4 years ago
how many moles of iron will be produced from 6.20 moles of carbon monoxide reacting with excess iron (III) oxide (FeO3) to produ
Gelneren [198K]

0.20 moles of iron will be formed in the reaction.

Explanation:

The balanced chemical equation for the reaction between iron (iii) oxide and carbon monoxide to form Fe is to be known first.

the balanced reaction is :

Fe2O3 + 3CO⇒ 2 Fe + 3 CO2

so from the data given the number of moles of carbon monoxide can be known:

3 moles of CO reacted with Fe2O3 to form 2 moles of iron in the reaction.

Number of moles of CO is 6.20 moles

11.6 gm of iron is formed

so the number of moles of iron formed is calculated as

n = mass of iron ÷ atomic weight of iron

  = 11.6 ÷ 55.84

  = 0.20 moles of iron will be formed when 11.6 gram of iron is produced.

5 0
3 years ago
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