Answer:
Reactants: Ethanol (C₅H₅OH), Oxygen (O₂)
Products: Carbon dioxide (CO₂) and Water (H₂O)
Explanation:
Let’s rewrite each part of the described situation in chemical equation terms.
Ethanol - C₂H₅OH
is burned in the prescence of - +
oxygen - O₂
producing - →
carbon dioxide - CO₂
and - +
water - H₂O
Chemical equation:
C₂H₅OH + O₂ → CO₂ + H₂O
The terms on the left side of a chemical equation are reactants, and the terms on the right side of a chemical equation are products.
Therefore, since we know this, ethanol (C₂H₅OH) & oxygen (O₂) are the reactants, and carbon dioxide (CO₂) & water (H₂O) are the products.
Answer:
False
Explanation:
Diffusion uses the concentration gradient that has been set up, this is a naturally occurring phenomena, and using a diffusion gradient some small particles can cross over the cell membrane. Some bigger or polar molecules require facilitated diffusion to move these molecules across the membrane.
Facilitated diffusion still uses the gradient for passive transport. This means that ATP is not used to transport molecules.
The reason that glucose will not move into the cell via passive transport is because there is a higher concentration of glucose inside the cell, meaning it needs active transport to move glucose (against the concentration gradient) into the cell.
Answer: Kinetic Energy is already moving and is not at rest. Potential Energy is purely based on the position of the object and also the condition of the object.
Explanation: hope this helps
Answer: Equilibrium concentration of ![[Cl^-]](https://tex.z-dn.net/?f=%5BCl%5E-%5D)
at 
is 4.538 M
Explanation:
Initial concentration of 
= 0.056 M
Initial concentration of 
= 4.60 M
The given balanced equilibrium reaction is,
![COCl_2+2Cl^-\rightleftharpoons [CoCl_4]^{2-}+6H_2O](https://tex.z-dn.net/?f=COCl_2%2B2Cl%5E-%5Crightleftharpoons%20%5BCoCl_4%5D%5E%7B2-%7D%2B6H_2O)
Initial conc. 0.056 M 4.60 M 0 M 0 M
At eqm. conc. (0.056-x) M (4.60-2x) M (x) M (6x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CoCl_4]^{2-}\times [H_2O]^6}{[CoCl_2]^2\times [Cl^-]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCoCl_4%5D%5E%7B2-%7D%5Ctimes%20%5BH_2O%5D%5E6%7D%7B%5BCoCl_2%5D%5E2%5Ctimes%20%5BCl%5E-%5D%5E2%7D)
Given : equilibrium concentration of ![[CoCl_4]^{2-}](https://tex.z-dn.net/?f=%5BCoCl_4%5D%5E%7B2-%7D)
=x = 0.031 M
Concentration of = (4.60-2x) M = 
=4.538 M
Thus equilibrium concentration of at is 4.538 M
First put the choices,and the answer is <span>(10^-3L/1mL)^3 is the correct answer.</span>
