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Radda [10]
3 years ago
5

50 points for who ever helps 5√x 14 simplify

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

This is actually really simple if you think about it.

5√x 14

5 × 14 = 70

=70√x

Therefore your answer is

70√x

I hope that this has satisfied you.

mina [271]3 years ago
5 0

Answer:

5√14x

Step-by-step explanation:

reorder factors, let me know if im right

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What is the sequence of second differences for ax +b?
MAVERICK [17]

Answer:

ZERO

Step-by-step explanation  

Write the given function as

F(x) = ax + b

i.e Y = ax + b

now differentiate Y with respect to X

dY/dX = d (ax + b)/ dx

dY/dX = a

now again differentiate this function with respect to x

so,  d^2Y/dX^2 = d^2 (a)/dX^2

                         = 0 (ZERO)

note: differentiation of constant function is zero

4 0
3 years ago
Can someone answer this? 8x^{-2/3}
Leya [2.2K]

Answer:

1 / 4 = 0. 25

Step-by-step explanation:

8x^{-2/3}

= 1 / 4

= 0. 25

mark brainliest

7 0
3 years ago
There are 6 times as many males as females on the maths course at university. What fraction of the course are female?
Leona [35]
1/7 of the course would be female.
7 0
3 years ago
What is the area of a circle with a circumference of 36.68 units
Lina20 [59]

Answer:

radius = circumference / (2 * PI)

radius = 5.8378033126

Circle Area = PI * radius^2

Circle Area = PI * 5.8378033126^2

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Step-by-step explanation:

4 0
3 years ago
A simple random sample of 85 students is taken from a large university on the West Coast to estimate the proportion of students
ahrayia [7]

Answer:

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the sample size 'n' = 85

The sample proportion

            p = \frac{x}{n} = \frac{51}{85} = 0.6

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p(1-p)}{n} })

<u><em>Step(ii):-</em></u>

Given that the level of significance

α = 0.05

Z₀.₀₅ = 1.96

(0.6 -1.96 \sqrt{\frac{06(1-06)}{85} } , 0.6 +1.96 \sqrt{\frac{0.6(1-0.6)}{85} })

(0.6 - 0.104138 , 0.6 +0.104138)

(0.4958 , 0.7041)

<u><em>Final answer:-</em></u>

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

6 0
3 years ago
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