6,3 L = 6300 mL
..................
1,79×10^-4g -------- 1 mL
Xg --------------------- 6300 mL
X = 0,000179×6300
X = 1,1277g ≈ 1,1g
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The correct electronic configuration of vanadium 23 is
1s^22s^22p^63s^23p^64s^23d^3
This electronic configuration is correct because it obeys the Aufbau principle which state that electrons fill the atomic orbital of the lowest energy before occupying the higher level. S orbital can occupy a total of 2 electrons, p orbital can occupy a total of 6 electrons while d orbital can occupy a total of 10 electrons. in the electronic configuration above an s orbital is filled before p orbital while the p orbital is filled before the d orbital .
In chemistry and physics, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.
Answer:
A
Explanation:
10,000g
just multiply the amount of hectograms by 100 to get grams
Answer:
c ammonium hydroxide nh4oh has higher ph value and its a base
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