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VikaD [51]
3 years ago
11

A chemical reaction can start when enough activation energy is added to the reactants. Do you think the activation energy for ch

emical reactions in living things is high or low/ Explain your answer
Chemistry
2 answers:
pav-90 [236]3 years ago
8 0
I think the best answer would be high. A chemical reaction can start when enough activation energy is added to the reactants. In living things the activation energy for chemical reactions is high. Because enzymes are present in cells in order to speed up reactions and give an alternative way for the reaction to occur.
e-lub [12.9K]3 years ago
7 0
High, the enzymes in cells function or speed up reactions by lowering the activation energy.
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Who was the scientist responsible for the theory of evolution by natural selection?
Allushta [10]

Answer:

Charles Darwin

Explanation:

Charles Darwin is more famous than his contemporary Alfred Russel Wallace who also developed the theory of evolution by natural selection. scientist who studies living organisms.J

8 0
3 years ago
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Sodium azide decomposes rapidly to produce nitrogen gas.
brilliants [131]

Answer:

156 g

Explanation:

Let's consider the following reaction.

2 NaN₃(s) → 2 Na(s) + 3 N₂ (g)

We can find the moles of N₂  using the ideal gas equation.

P × V = n × R × T

1.50 atm × 60.0 L = n × (0.08206 atm.L/mol.K) × 305 K

n = 3.60 mol

The molar ratio of N₂ to NaN₃ is 3:2. The moles of NaN₃ are:

3.60 mol N₂ × (2 mol NaN₃ / 3 mol N₂) = 2.40 mol NaN₃

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

2.40 mol × 65.01 g/mol = 156 g

4 0
3 years ago
HURRRY IM BEING TIMED
hichkok12 [17]

Answer:

C) 4s2

Explanation:

6 0
3 years ago
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At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i
olganol [36]

Answer:

K_c=0.0867

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.760}{1.50\ L}

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.130}{1.50\ L}

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}  

K_c=\frac{(0.3334)^2\times 0.0867}{(0.3334)^2}

K_c=0.0867

5 0
3 years ago
У 2грамах воднню скільки молекул і скільки атомів<br>​
Alekssandra [29.7K]

In 2 g H₂ there are 6,023.10²³ molecules H₂ and 2 x 6,023.10²³ atoms H

<h3>Further explanation </h3>

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

 

The question is :

<em>in 2 grams of hydrogen how many molecules and how many atoms</em>

  • mol of Hydrogen - H₂

MW H₂ = 2.01568 u  (2 atoms of H)

MW H = 1.00784 u

\tt mol=\dfrac{m}{MW}\\\\mol=\dfrac{2~g}{2.01568 u}=0.992

  • number of molecules

\tt 0.992\times 6.02\times 10^{23}=5.97\times 10^{23}

  • mol of H

\tt mol=\dfrac{2}{1.00784}= 1.984

  • number of atoms

\tt 1.984\times 6.02\times 10^{23}=11.94\times 10^{23}

Or a simply way :

1 g of H atoms = 1 mol of H  (MW H = 1 g/mol)

2 g of H atoms (in 2 gr H₂) = 2 moles of H  

2 g of H₂ molecules = 1 mole of H₂  (MW H₂=2 g/mol)

so in 2 g H₂ there are 6,023.10²³ molecules H₂ and 2 x 6,023.10²³ atoms H

4 0
3 years ago
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