Answer: ^_^
Explanation:
its because during day time the ball becomes heated up and the air inside it try to come out as the heat air always try to go up swelling up the ball,
so in the evening when the air cools down the ball too cools down and air inside it also cools down making the ball feel soft,
Therefore, a football feels hard on a hot day but feels softer in the evening
Hope it helped u,
pls mark as the brainliest
^_^
Answer: Option (3) is the correct answer.
Explanation:
Atomic number of lithium is 3 and its electronic distribution is 2, 1. So, to attain stability it will loose an electron and hence, it forms a single bond.
Atomic number of chlorine is 17 and it has 7 valence electrons. Hence, in order to attain stability it will gain one electron and therefore, it forms a single bond only.
Atomic number of nitrogen is 7 and its electronic distribution is 2, 5. Therefore, to attain stability it needs to gain 3 more electrons. Hence, a nitrogen atom is able to form a triple bond and also it is able to form a double bond.
Hydrogen has atomic number 1 and it attains stability by gaining one electron. Therefore, a hydrogen atoms always forms a single bond.
Atomic number of fluorine is 9 and its electronic distribution is 2, 7. To complete its octet it needs to gain one electron. Hence, a fluorine atom always forms a single bond.
Thus, we can conclude that out of the given options nitrogen is most likely to form multiple (double or triple) bonds.
Answer:
The diameter of the hydrogen 
Explanation:
From the given information:
Using the concept of Bohr's Model, the equation for the angular momentum can be expressed as:
Where the generic expression for angular momentum is:
L = mvr.
replacing the value of L into the previous equation, we have:
----- (1)
The electron in the hydrogen atom posses an electrostatic force which gives a centripetal force.
----- (2)
replacing the value of v in equation (1) into (2), and taking r as the subject of the formula, we have:
For ground-state n = 1
Therefore, the diameter of hydrogen d = 2r
