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Leno4ka [110]
3 years ago
13

What gravitational force does the moon produce

Physics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

1.94\cdot 10^{20} N

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

The gravitational force is always attractive.

In this problem, we have:

m_1 = 5.98\cdot 10^{24}kg is the mass of the Earth

m_2 = 7.34\cdot 10^{22} kg is the mass of the Moon

r=3.88\cdot 10^8 m is the separation between the Earth and the Moon

Therefore, the gravitational force between them is

F=(6.67\cdot 10^{-11})\frac{(5.98\cdot 10^{24})(7.34\cdot 10^{22})}{(3.88\cdot 10^8)^2}=1.94\cdot 10^{20} N

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In a perfectly elastic collision between two perfectly rigid objects
ipn [44]

Both the total momentum and the total kinetic energy are conserved

Explanation:

- In a collision between two or more objects, if there are no external forces acting on the system (isolated system), the total momentum of the objects is always conserved. This is called principle of conservation of momentum, and can be written as follows:

mu+MU = mv+MV

where

m, M are the masses of the two objects

u, U are the initial velocities of the two objects

v, V are the final velocities of the two objects

- The total kinetic energy, however, is not always conserved. In fact, we have two types of collision:

1) In a perfectly elastic collision, the total kinetic energy of the objects is conserved. This means that we can write the following equation:

\frac{1}{2}mu^2 + \frac{1}{2}MU^2 = \frac{1}{2}mv^2+\frac{1}{2}MV^2

2) In an inelastic collision, the total kinetic energy of the object is NOT conserved. This means that part of the total kinetic energy is "lost", converted into other forms of energy (mainly thermal energy, due to the presence of frictional forces within the system). The most extreme case is called perfectly inelastic collision, in which the two objects stick together after the collision, and there is the maximum loss of kinetic energy.

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

LearnwithBrainly

7 0
4 years ago
What is the energy transformation when a boy rides a bicycle​
castortr0y [4]

Answer:

energy transform mechanical to motion

8 0
3 years ago
A standard biological microscope is required to have a magnification of 200Ã. what is the focal length of the objective?
NISA [10]

Answer:

The focal length of the objective is L/20.

Explanation:

Given that,

Magnification of the standard biological microscope, m = 200

Let the magnification of the eyepiece is, m_e=10

Let m_o is the magnification of objective lens. The formula of the magnification is given by :

M=m_o\times m_e\\\\200=m_o\times 10\\\\m_o=20

The formula of the magnification is given by :

M=\dfrac{L}{f_o}m_e

L is length of microscope

f_o is focal length of the objective

f_o=\dfrac{Lm_e}{M}\\\\f_o=\dfrac{10L}{200}\\\\f_o=\dfrac{L}{20}

So, the focal length of the objective is L/20.

7 0
3 years ago
What is the force due to gravity of a 38 kg student?
alukav5142 [94]

Answer:

F_g = 372.78 N

Explanation:

Formula for force of gravity is;

F_g = mg

Where;

m is mass

g is acceleration due to gravity

We are given;

Mass = 38 kg

Acceleration due to gravity has a constant value of 9.81 m/s²

Thus;

F_g = 38 × 9.81

F_g = 372.78 N

6 0
3 years ago
When you shoulder your shotgun, what part of your body should fit snugly against the stock?
Troyanec [42]

Answer:

Cheek

Explanation:

Typically the scope is a bead on the gun's edge. Our eye must be in alignment with the muzzle, so that the proper placement of our head on the stock is crucial. The stock will fit snugly to our cheek as we put the pistol to our face with our head on other side just above gun's center line.

The correct answer is cheek.

8 0
3 years ago
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