What gravitational force does the moon produce
1 answer:
Answer:
Explanation:
The magnitude of the gravitational force between two objects is given by the equation:
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
The gravitational force is always attractive.
In this problem, we have:
is the mass of the Earth
is the mass of the Moon
is the separation between the Earth and the Moon
Therefore, the gravitational force between them is
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Answer:
120 m
Explanation:
Given:
wavelength 'λ' = 2.4m
pulse width 'τ'= 100T ('T' is the time of one oscillation)
The below inequality express the range of distances to an object that radar can detect
τc/2 < x < Tc/2 ---->eq(1)
Where, τc/2 is the shortest distance
First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'
f = c/λ (c= speed of light i.e 3 x m/s)
f= 3 x / 2.4
f=1.25 x hz.
As, T= 1/f
time of one oscillation T= 1/1.25 x
T= 8 x s
It was given that pulse width 'τ'= 100T
τ= 100 x 8 x => 800 x
s
From eq(1), we can conclude that the shortest distance to an object that this radar can detect:
= τc/2 => (800 x
x 3 x
)/2
=120m
<h2>Answer: 13.61 N/m</h2>
Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force applied to it, <u>as long as the spring is not permanently deformed</u>:
(1)
Where:
is the elastic constant of the spring. The higher its value, the more work it will cost to stretch the spring.
is the length of the spring without applying force.
is the length of the spring with the force applied.
According to this, we have a spring where only the force due gravity is applied.
In other words, the force applied is the weigth of the block:
(2)
Where is the mass of the block and
is the gravity acceleration.
(3)
(4)
Knowing the force applied and
and
, we can substitute the values in equation (1) and find
:
(5)
(6)
<u>Finally:</u>