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A closed cylindrical can of fixed volume V has radius r.a) Find the surface area, S, as a function of r.b) What happens to the v

andrey2020 [161]

Answer:

Step-by-step explanation:

This question is incomplete; here is the complete question.

A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if V=10 cm³.

A closed cylindrical can of volume V is having radius r and height h.

a). Surface area of a cylinder is given by

S = 2(Area of the circular sides) + Lateral area of the can

S = 2πr² + 2πrh

S = 2πr(r + h)

b). Since surface area is directly proportional to radius of the can

S ∝ r

Therefore, when r approaches to infinity (r → ∞)

c). If V = 10 cm³ Then we have to graph S against r.

From the formula V = πr²h

10 = πr²h

h = $\frac{10}{\pi r^{2}}$

By placing the value of h in the formula of surface area,

S = $2\pi r(r+\frac{10}{\pi r^{2}})$

Now we can get the points to plot the graph,

r -2 -1 0 1 2

S -13.72 -13.72 0 26.28 35.13

7 0

4 years ago

It costs 3

yKpoI14uk [10]

Answer:

3g = 21

Step-by-step explanation:

TTM answer

6 0

3 years ago

I NEED ANSWER ASAP! I WILL GIVE BRAINELIEST!!!!!! Construct a right triangle whose legs are in the ratio 3:4. What are the ratio

Gala2k [10]

Answer:

3 : 5, 4: 5

Step-by-step explanation:

Let the common multiplier of the given ratios be x.

Therefore, lengths of the legs of right triangle would be 3x and 4x

By Pythagoras Theorem:

${hyp}^{2} = {(3x)}^{2} + {(4x)}^{2} \\ = 9 {x}^{2} + 16 {x}^{2} \\ = 25 {x}^{2} \\ hyp = \sqrt{25 {x}^{2} } \\ hyp = 5x \\ \\ ratios \: of each \: leg \: to \: the \: hypotenuse \\ \frac{3x}{5x} = 3 : 5 \\ \\ \frac{4x}{5x} = 4 : 5$

5 0

3 years ago

The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =

avanturin [10]

Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5

The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35

Therefore, the zeros of the quadratic equation are 1.85 and -1.35.

4 0

3 years ago

Read 2 more answers

Find the x and y intercepts of the following function.<br> g(x)=x^2-5x-84

Ahat [919]

Answer:

see explanation

Step-by-step explanation:

To find the y- intercept let x = 0 in the function

g(0) = 0 - 0 - 84 = - 84 ← y- intercept

To find the x- intercepts let y = 0, that is

x² - 5x - 84 = 0

To factor the quadratic

Consider the factors of the constant term (- 84) which sum to give the coefficient of the x- term

The factors are - 12 and + 7, since

- 12 × 7 = - 84 and - 12 + 7 = - 5, thus

(x - 12)(x + 7) = 0

Equate each factor to zero and solve for x

x - 12 = 0 ⇒ x = 12

x + 7 = 0 ⇒ x = - 7

x- intercepts are x = - 7 and x = 12

8 0

3 years ago