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ki77a [65]
3 years ago
12

Pretty please help me with this thank you guys so much!

Mathematics
1 answer:
Bingel [31]3 years ago
7 0
13. -48/-6 is the greater quotient because the same signs are always going to be a positive number

14. If they start with 4, the easy way would be to multiply 2 by -5 and then to add -10 and 4 which would give you -6 points
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1.Write 6,730,000 in scientific notation.
miskamm [114]

Answer:

6.73 X 10 to the sixth power.

1.33 X 10 to the fifth power.

9.77 X 10 to the twenty-second power.

Step-by-step explanation:

7 0
4 years ago
There were 90 boys at the Hammarskjold school dance. They made up 60% of all of the students there. How many total students were
Harman [31]

Answer:

The answer would be 150

Step-by-step explanation:

8 0
3 years ago
Which trigonometric ratios are correct for triangle ABC? Check all that apply
sergij07 [2.7K]
Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and 
HYP denote the hypotenuse.

then: 

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ


Back to our problem, 

using the Pythagorean we can find the length of AB: 

|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 


Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}
Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}
Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}
Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}
Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}


Answer: 1, 3, 4



5 0
3 years ago
For two real numbers A and B, A is either equal to B or greater than B
umka2103 [35]

Step-by-step explanation:

it's this > with _ under it

7 0
3 years ago
What size does the radius of a sphere need to be for its volume to be larger than its surface area? HINT! It is less than 10. HI
Lera25 [3.4K]
We know that
volume of a sphere=(4/3)*pi*r³----> (r/3)*(4*pi*r²)
and
surface area of sphere=4*pi*r²
so
the volume of a sphere=(r/3)*surface area of sphere
therefore
if r=3
volume of a sphere=(3/3)*surface area of sphere
volume of a sphere=surface area of sphere

if r> 3
the term (r/3) is > 0
so
volume of a sphere > surface area of sphere

if r<3
the term (r/3) is < 0
so
volume of a sphere < surface area of sphere

examples
1) for radius r=3 units
volume of a sphere=(4/3)*pi*3³----> 113.04 unit³
surface area=4*pi*3²----> 113.04 units²
volume is equal to surface area

2) for radius r=10 units
volume of a sphere=(4/3)*pi*10³----> 4186.67 unit³
surface area=4*pi*10²----> 1256 units²
volume is > surface area

3) for radius r=2 units
volume of a sphere=(4/3)*pi*2³----> 33.49 unit³
surface area=4*pi*2²----> 50.24 units²
volume is <  surface area
7 0
3 years ago
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