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Gnom [1K]
3 years ago
5

PLZ HELP HURRY 20 POINT

Physics
1 answer:
Andre45 [30]3 years ago
6 0
The lungs art part of The excretory<span> system....
</span><span>somatic nervous system is ..... </span><span>autonomic nervous system<span>....
</span></span>
The process in which organ systems work to maintain a stable internal environment is called homeostasis. Keeping a stable internal environment requires constant adjustments. Here are just three of the many ways that human organ systems help the body maintain homeostasis:
Respiratory system: A high concentration of carbon dioxide in the blood triggers faster breathing. The lungs exhale more frequently, which removes carbon dioxide from the body more quickly.
Excretory system: A low level of water in the blood triggers retention of water by the kidneys. The kidneys produce more concentrated urine, so less water is lost from the body.
Endocrine system: A high concentration of sugar in the blood triggers secretion of insulin by an endocrine gland called the pancreas. Insulin is a hormone that helps cells absorb sugar from the blood.
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What happens to the boiling point of water when the pressure is increased?
Artemon [7]
You can drink it nothing will happen you caN BOIL ME SOME EGGS IF YOU WANT TOO
4 0
3 years ago
What climate factor is responsible for the snow on my Kilimanjaro
Nimfa-mama [501]
The climate factor that is responsible for the amount of snow on Mt. Kilimanjaro is high elevation. In the concept of precipitation, as an air mass rises and cools, its capacity to hold water vapor lessens. This vapor condenses into water droplets, forming clouds. Terrain with high elevation attracts such formations, bringing with them cloudiness, rainfall, and snowfall. 
4 0
3 years ago
A distant large asteroid is detected that might pose a threat to Earth. If it were to continue moving in a straight line at cons
Vlada [557]

Answer:

The minimum speed required is 5.7395km/s.

Explanation:

To escape earth, the kinetic energy of the asteroid must be greater or equal to its gravitational potential energy:

K.E\geq P.E

or

\dfrac{1}{2}mv^2 \geq  G\dfrac{Mm}{R}

where m is the mass of the asteroid, R= 24,000,000\:m is its distance form earth's center, M = 5.9*10^{24}kg is the mass of the earth, and G = 6.7*10^{-11}m^3/kg\: s^2 is the gravitational constant.

Solving for v we get:

v \geq \sqrt{\dfrac{2GM}{R} }

putting in numerical values gives

v \geq \sqrt{\dfrac{2(6.7*10^{-11})(5.9*10^{24})}{(24,000,000)} }

\boxed{v\geq 5739.5m/s}

in kilometers this is

v\geq5.7395m/s.

Hence, the minimum speed required is 5.7395km/s.

5 0
3 years ago
If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle
soldi70 [24.7K]

Answer:

The angle that the wave would be \theta = sin ^{-1}\frac{2 \lambda}{D}

Explanation:

From the question we are told that  the  opening to  the  harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the  on at angle greater than the diffraction first minimum would be slightly affected

  The minimum is as a result of destructive interference

       And for single-slit this is mathematically represented as

               D sin \ \theta =m \lambda

where D is the slit with

          \theta is the angle relative to the original direction of the wave

         m is the order of the minimum j

        \lambda is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

      And the both is safe at the angle equal to the second minimum then

    The the angle is evaluated as

           \theta = sin ^{-1}[\frac{m\lambda}{D} ]

Since for second minimum m= 2

The  equation becomes

               \theta = \frac{2 \lambda}{D}

3 0
3 years ago
Imagine a particle that has three times the mass of the electron. All other quantities given above remain the same. What is the
melamori03 [73]

Answer:

The only parameter that changes is mass m

It is only necessary to calculate the ratio Eh/Ee

m_{h}=3m_{e}\\E_{h}=\frac{3m_{e}v^{2}}{2}\\E_{e}=\frac{m_{e}v^{2}}{2}\\\frac{E{h}}{E{e}}=3

The kinetic energy of the heavy paricle is three times the kinetic energy of an electron

5 0
3 years ago
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