Answer:
d = 4180.3m
wavelengt of sound is 0.251m
Explanation:
Given that
frequency of the sound is 5920 Hz
v=1485m/s
t=5.63s
let d represent distance from the vessel to the ocean bottom.
an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.


wavelengt of sound is
= v/f
= (1485)/(5920)
= 0.251 m
Answer:
The following explanatory section gives an explanation of this question.
Explanation:
- This means that perhaps the bubble moves more than a certain duration throughout the calibration breath meter offers the rate as well as oxygenation consumed inside this cell.
- Inside that respirometer, oscillation of something like the bubble gave a technique of multiplying the quantity of oxygenation that is used by the seedlings mostly through cell membrane breathing.
Answer:
434 Hz
Explanation:
According to the Doppler effect, when a source of a wave is moving towards an observer at rest, then the observer will observe an apparent frequency which is higher than the original frequency of the source.
In this situation, Tina is driving towards Rita. Tina is the source of the sound wave (the horn), while RIta is the observer. Since the original frequency of the sound is 400 Hz, Rita will hear a sound with a frequency higher than this value.
The only choice which is higher than 400 Hz is 434 Hz, so this is the frequency that Rita will hear.
Answer:
<u><em>A.)</em></u> The particles that make up material A have more mass than the
particles that make up material B.
HOPE that helps!!! :)
Answer:
3. µs g /7
Explanation:
The largest Force appear when the maximal friction Force is required.
Second Newton law for the small block:
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

Second Newton law for the Big Block:


