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ira [324]
3 years ago
5

Amanda's younger brother tells her that he saw a comet with a long and bright tail move rapidly across the sky. Amanda tells him

that it was not a comet. Which statement explains why Amanda is correct?
A.Comets do not have tails.
B.Comets are not ever visible from Earth.
C.Comets are not a part of our Solar System.
D.Comets don't move rapidly across the sky.
Chemistry
2 answers:
spayn [35]3 years ago
4 0

it would be B.Comets are not ever visible from Earth.

Comets travel very fast, loop around the Sun, and have long tails. A comet is a chunk of material left over from the formation of the solar system. ... Because the comets are much smaller and lighter than planets, they are easily pulled this way and that by the gravity of the planets (or, in some cases, even by stars).

Yes. All of the comets in the Kuiper Belt and Oort Cloud are part of the solar system. They orbit our Sun, and obey the same laws of motion as the planets and their moons. Comets also started with the same materials that planets like Earth were made from.

Halley's Comet, for example, is usually very bright when it passes through the inner Solar System every seventy-six years, but during its 1986 apparition, its closest approach to Earth was almost the most distant possible. The comet became visible to the naked eye, but was unspectacular.

As a comet approaches the Sun, it starts to heat up. The ice transforms directly from a solid to a vapor, releasing the dust particles embedded inside. Sunlight and the stream of charged particles flowing from the Sun – the solar wind – sweeps the evaporated material and dust back in a long tail.

kolezko [41]3 years ago
3 0

D. Comets don't move rapidly across the sky.

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Answer:

PLUTO

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Explanation:

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The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av
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<u>Answer:</u> The percentage abundance of _{77}^{191}\textrm{Ir} and _{77}^{193}\textrm{Ir} isotopes are 37.10% and 62.90% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{77}^{191}\textrm{Ir} isotope be 'x'. So, fractional abundance of _{77}^{193}\textrm{Ir} isotope will be '1 - x'

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Mass of _{77}^{191}\textrm{Ir} isotope = 190.9606 amu

Fractional abundance of _{77}^{191}\textrm{Ir} isotope = x

  • <u>For _{77}^{193}\textrm{Ir} isotope:</u>

Mass of _{77}^{193}\textrm{Ir} isotope = 192.9629 amu

Fractional abundance of _{77}^{193}\textrm{Ir} isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710

Percentage abundance of _{77}^{191}\textrm{Ir} isotope = 0.3710\times 100=37.10\%

Percentage abundance of _{77}^{193}\textrm{Ir} isotope = (1-0.3710)=0.6290\times 100=62.90\%

Hence, the percentage abundance of _{77}^{191}\textrm{Ir} and _{77}^{193}\textrm{Ir} isotopes are 37.10% and 62.90% respectively.

8 0
3 years ago
How many moles of MgSiO3 are in 199 g of the compound?
Leokris [45]
24.305 g +28.08 g + 3(15.999 g)=100.382
219 g MgSIO3 (1 mole MGSIO3/100.382g)=2.181 mol MgSIO3
the answer is 2.18 mol MgSIO3
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Yes is the answer :);)
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Answer: 2Cl^-(l)\rightarrow 2e^-+Cl_2(g)

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2NaCl(l)\rightarrow 2Na^++2Cl^-

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