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4 years ago

Why is helium nucleus containing no neutrons is likely to be unstable

1 answer:

8 0

A Helium nucleus is likely to be unstable if it has no neutrons because the remaining protons will repel electromagnetically and basically cause the atom to fall apart. The neutrons could have helped in holding everything together, and not make the protons repel.

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An atom of 14 6 c carbon decays by gamma decay which atom is left after the decay

ladessa [460]

Answer is: carbon.

During gamma emission the nucleus emits radiation without changing its composition, if for example have nucleus with six protons and six neutrons (carbon atom) and after gamma decay there is nucleus with six protons and six neutrons.
Gamma rays are the electromagnetic waves with the shortest wavelengths (1 pm), highest frequencies (300 EHz) and highest energy (1,24 MeV).

7 0

4 years ago

Read 2 more answers

Decane (C10H22) is used in diesel. The combustion for decane follows the equation: 2 C10H22 + 31 O2 à 20 CO2 + 22 H2O. Calculate

creativ13 [48]

The mass of water produced is 792 grams by the combustion of 568 grams of decane.

Given:

Combustion of 568 grams of decane with 2979 grams of oxygen.

$2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O$

To find:

The mass of water produced by combustion of 568 grams of decane.

Solution:

Mass of decane = 568 g

Moles of decane :

= $\frac{568 g}{142 g/mol}=4 mol$

Mass of oxygen gas = 2976 g

Moles of oxygen gas:

= $\frac{2976 g}{32 g/mol}=93 mol$

$2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O$

According to reaction, 2 moles of decane reacts with 31 moles of oxygen, then 4 moles of decane will react with:

$=\frac{31}{2}\times 4mol=62\text{ mol of}O_2$

But according to the question, we have 93.0 moles of oxygen gas which is more than 62 moles of oxygen gas.

So, this means that oxygen gas is present in an excessive amount. Which simply means:

Oxygen gas is an excessive reagent.
Decane is a limiting reagent.
Decane being limiting reagent will be responsible for the amount of water produced after the reaction.

According to reaction, 22 moles of water is produced from 2 moles of decane, then 4 moles of decane will produce:

$=\frac{22}{2}\times 4mol=44\text{mol of }H_2O$

Mass of 44 moles of water ;

$=44mol\times 18g/mol=792g$

792 grams of water is produced by the combustion of 568 grams of decane.

Learn more about limiting reagent and excessive reagent here:

brainly.com/question/14225536?referrer=searchResults

brainly.com/question/7144022?referrer=searchResults

3 0

3 years ago

Complete the sentence using oxalate, oxic or oxide

Hitman42 [59]

Answer: oxide

Explanation:..

8 0

3 years ago

Hydrogen may not be advantagous as a fuel because-------

sergeinik [125]

Answer:

Hydrogen may not be advantageous as a fuel because...

- Its expensive

- Its difficult to store

- Its highly flammable

- Its dependent on fossil fuels

Explanation:

Its expensive - Not only is hydrogen gas expensive, but it also takes a lot of work to free from other elements. It is both expensive and time-consuming to produce.

Its difficult to store - Moving hydrogen is not an easy task. Moving anything more than small amounts of hydrogen was also very expensive, making it impractical.

Its highly flammable - When exposed to the atmosphere, hydrogen could potentially form explosive mixtures.

Its dependent on fossil fuels - Hydrogen energy itself is renewable. However, the process of separating it from oxygen uses non-renewable sources such as coal and oil.

~Hope this Helps!~

7 0

3 years ago

HELP PLEASE.

Dafna11 [192]

This hypothetical process would produce actinium-230.

<h3>Explanation</h3>

An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.

There are two types of beta decay: beta minus β⁻ and beta plus β⁺.

The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.

β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.

Gamma decays do not influence the atomic or mass number of a nucleus.

Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.

The overall nuclear reaction would involve five different particles. On the reactant side, there is

one uranium-238 atom.

On the product side, there are

one actinium-230 atom,
two alpha particles (a.k.a. helium-4 nuclei),
one electron, and
one gamma particle (a.k.a. photon).

$\;_{\phantom{2}92}^{238} \text{U} \to \;_{\phantom{2}89}^{230} \text{Ac} + \;_{2}^{4} \text{He} + \;_{2}^{4} \text{He} + \text{e}^{-} + \gamma$

Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?

8 0

3 years ago