Answer:
B) Alcohol
Explanation:
It is methanol. Alcohol has group 'OH'
Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecules by Hydrogen bonds.
Hydrogen Bond
Between a hydrogen (H) atom that is covalently bonded to a more electronegative "donor" atom or group and another electronegative atom bearing a lone pair of electrons—the hydrogen bond acceptor—a hydrogen bond (or H-bond) forms (Ac). The second-row elements fluorine, oxygen, and nitrogen are the most common donor and acceptor atoms (F).
It may take place either intramolecularly or intermolecularly (between different molecules) (occurring among parts of the same molecule). The energy of a hydrogen bond can range from 1 to 40 kcal/mol and is influenced by the shape, surroundings, and nature of the particular donor and acceptor atoms.
To learn more about the hydrogen bond refer here:
brainly.com/question/10904296
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Silver chloride is simply AgCl while silver is Ag so we
see that there is one mole to one mole correspondence. First calculate the
moles of Ag:
moles Ag = 5.8 g / ( 107.87 g/mol)
moles Ag = 0.0538 mol
Then the mass of AgCl required:
mass AgCl = 0.0538 mol * 143.32 g/mol
<span>mass AgCl = 7.71 grams</span>
Answer:
The concentration after 115 seconds is 0.0496 M
Explanation:
Applying integrated rate law for a first-order reaction, we will have;
![[A]_t = [A]_0e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%5BA%5D_0e%5E%7B-kt%7D)
where;
![[A]_t](https://tex.z-dn.net/?f=%5BA%5D_t)
is the concentration at a time t
![[A]_0](https://tex.z-dn.net/?f=%5BA%5D_0)
is the initial concentration
k is the rate constant for the reaction
t is the given time
Given;
= 0.05 M
k = 6.2 x 10⁻⁵ mol L⁻¹s⁻¹
t = 115 seconds
Substitute these values and solve for
![[A]_t = [A]_0e^{-kt} = (0.05)*e^{-(6.2X10^{-5}*115)}\\\\](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%5BA%5D_0e%5E%7B-kt%7D%20%3D%20%280.05%29%2Ae%5E%7B-%286.2X10%5E%7B-5%7D%2A115%29%7D%5C%5C%5C%5C)
![[A]_t = (0.05)(0.9929) =0.0496 M](https://tex.z-dn.net/?f=%5BA%5D_t%20%3D%20%280.05%29%280.9929%29%20%3D0.0496%20M)
Therefore, the concentration after 115 seconds is 0.0496 M
Answer:
Explanation:
Hello,
In this case, the reaction between sodium and ammonia is:
Thus, as we know the initial masses of both sodium and ammonia, we should first identify the limiting reactant, for which we firstly compute the available moles of sodium:
And the moles of sodium consumed by 21.4 g of ammonia (2:2 mole ratio):
In such a way, since less moles of sodium are available than consumed by ammonia, we can say, sodium is the limiting reactant. Furthermore, the mass of both sodium amide (39 g/mol) and hydrogen gas (2 g/mol) that are produced turn out:
Best regards.
