Answer:
Average rate of reaction is 0.000565 M/min
Explanation:
Applying law of mass action for the given reaction:
Average rate = ![-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO_{2}]}{\Delta t}=\frac{\Delta [O_{2}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5CDelta%20%5BNO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B%5CDelta%20%5BO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
Where, ![-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of disappearance of 
, ![\frac{1}{4}\frac{[NO_{2}]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5BNO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of appearance of 
and ![\frac{[O_{2}]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of appearance of 
Here,![-\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
= 
So average rate of reaction = ![[tex]-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=%5Btex%5D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
[/tex] = 
Answer: Manholes are usually round, primarily because roundness is the best shape to resist the compression of the earth; covers are round because they are easier to manufacture than square or rectangular shapes, they are easier to move by rolling, and they can't fall into the opening.
Explanation:
Answer:
D) 3.51x10²³ formula units
Explanation:
To know this, we need to calculate the molecular mass of CaO. To do that, let's use the atomic mass of each element of this compound.
Ca: 40.08 g/mol; O: 16 g/mol
With these given AM, let's calculate the molar mass of CaO:
Mm CaO = 40.08 + 16 = 56.08 g/mol
Now that we have the MM of CaO, it's time to determine the moles of CaO:
moles = mass / MM
moles = 32.7 / 56.08 = 0.5831 moles
Finally to get the formula units, we need to use the Avogadro's number which is 6.02x10²³. According to this number, 1 mole of any substance has this number of atoms, molecules or formula units. So, if we have 0.5831 moles, then the formula units will be:
FU = 0.5831 * 6.02x10²³
<h2>
FU = 3.51x10²³ formula units</h2>
Hope this helps
need 0.500 x 0.125 = 0.0625 moles of NaOH. The molecular weight is 23+16+1 = 40, so 0.0625 x 40 = 2.5 grams will do the trick.
