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noname [10]
3 years ago
6

Suppose a certain candy is made up of​ red, yellow,​ green, blue, and orange pieces. ​a) If you draw one piece of​ candy, are th

e events of getting a green one and getting a yellow one​ disjoint, independent, or​ neither? ​b) Assume you have an infinite supply of these candy pieces from which to draw. If you draw two pieces one right after the​ other, are the events of getting a blue on the first and a blue on the second​ disjoint, independent, or​ neither? ​c) Can disjoint events ever be​ independent? Explain.
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

(a) Disjoint

(b) Independent

(c) No

Explanation:

(a) Disjoint events are those events that are mutually exclusive or we can say that the two events can not occur at the same instant.

Thus in a single draw we can not get both yellow and green ball.

(b) Those events in which the probability of the occurrence of one event does not affect the probability of the happening of another event in any way.

Thus the two pieces drawn are from the infinite supply does not affect one another and hence are independent.

(c) No, since after one event has occurred the occurrence of the other one is not possible.

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Let A and B be sets with cardinal numbers , n(A) = a and n(B) = b respectively . Decide whether the statement is true or false.
olya-2409 [2.1K]

Answer:

True

Step-by-step explanation:

A\cup B=A\cup(A-B)\\\\A\ and\ A-B\ are\ disjoint\ that\ means\ there\ is\ no\ common\ element\ in\ these\ two.\\\\n(A\cup B)=n(B\cup(A-B))\\\\n(A\cup B)=n(B)+n(A-B)\ \ \ \ \ \ \ as\ for\ disjoint\ set\ P,Q\ n(P\cup Q)=n(P)+n(Q)\\\\(n(P-Q)=n(P)-n(P\cap Q))\\\\n(AUB)=n(B)+n(A-B)\\\\n(AUB)=n(B)+n(A)-n(A\cap B)\\\\n(AUB)=n(A)+n(B)-n(A\cap B)\\\\Hence\ given\ statement\ is\ true

4 0
3 years ago
Which transformation shows that the two given circles are similar?
gregori [183]
Circle A -- center(2, 0), radius 8 Circle A' -- center(-1, 5), radius 3
3 0
3 years ago
All 203 students at Polk school eat lunch at the same time One day 19 students were absent if 8 students sit at each table yhw l
lisov135 [29]

Answer:

23 tables

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the area of the figure.
jasenka [17]
Divide into shapes that you can find the area of.....

you also have to cross out the 5 and the 4s because you will not need them

2×2= 4 sq. cm
2×2= 4 sq. cm
9×2 = 18 sq. cm

18 + 4 + 4 = 26 sq. cm

so the area is 26 sq. cm
6 0
3 years ago
For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 50
Volgvan

Answer:

P(\bar X>530)=1-0.808=0.192

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the scores, and for this case we know the distribution for X is given by:

X \sim N(\mu=505,\sigma=170)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(505,\frac{170}{\sqrt{35}})

2) Calculate the probability

We want this probability:

P(\bar X>530)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >530)=1-P(Z

P(\bar X>530)=1-0.808=0.192

3 0
3 years ago
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