Answer: Osmotic pressure : increases
Explanation:
Osmotic pressure is the minimum pressure which is applied to a solution to prevent the flow of solvent across a semipermeable membrane

= osmotic pressure
C= concentration in Molarity (number of moles of solute dissolved per liter of the solution)
R= solution constant
T= temperature
Thus as osmotic pressure is directly proportional top concentration, osmotic pressure will increase on increasing the concentration of a nonvolatile solute in water.
Answer:
Double bond
Explanation:
Carbon is a tetravalent atom. This implies that the carbon atom always forms four covalent bonds.
These four covalent bonds may be single, double or triple bonds. Compounds that contain double and triple bonds are said to be "unsaturated".
If the last carbon atom of an unsaturated fatty acid is bonded to two hydrogen atoms and one carbon atom, it means that the bond between the last carbon and the other carbon atom must be a double bond because carbon must be tetravalent and we have already been told that the fatty acid is unsaturated.
The last carbon atom of the unsaturated fatty acid must form two covalent bonds to the other carbon atom in order to respect the tetravalency of carbon.
Answer:
![[SO_2Cl_2]_{600}= 0.0842 M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D_%7B600%7D%3D%200.0842%20M)
Explanation:
Some theoretical knowledge is required here. We should understand that whenever we plot the natural logarithm, ln, of a concentration vs. time and obtain a straight line, this indicates a first-order reaction. That said, since this is the case here, we have a first-order reaction with respect to
.
The linear equation has the following terms:

It is a linear form of the integrated first-order law equation:
![ln[SO_2Cl_2]_t = -kt + ln[SO_2Cl_2]_o](https://tex.z-dn.net/?f=ln%5BSO_2Cl_2%5D_t%20%3D%20-kt%20%2B%20ln%5BSO_2Cl_2%5D_o)
Therefore, the rate constant, k, is:

The natural logarithm of initial molarity is:
![ln[SO_2Cl_2]_o = -2.30](https://tex.z-dn.net/?f=ln%5BSO_2Cl_2%5D_o%20%3D%20-2.30)
Using the equation, we may substitute for t = 600 s and obtain the natural logarithm of the concentration at that time:
![ln[SO_2Cl_2]_{600} = -0.000290 s^{-1}\cdot 600 s - 2.30 = -2.474](https://tex.z-dn.net/?f=ln%5BSO_2Cl_2%5D_%7B600%7D%20%3D%20-0.000290%20s%5E%7B-1%7D%5Ccdot%20600%20s%20-%202.30%20%3D%20-2.474)
Take the antilog of both sides to find the actual molarity:
![[SO_2Cl_2]_{600}=e^{-2.474} = 0.0842 M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D_%7B600%7D%3De%5E%7B-2.474%7D%20%3D%200.0842%20M)
A .
1 mol of sodium na atoms -22.99
22.99 x 8 =183.92
Closest answer