Question

In the following reaction, how many liters of o2 will produce 43.62 liters of co2 at stp? c3h8 5 o2 3 co2 4 h2o

Answer 1

Answer: 72.7 L

Explanation:

$C _3H_8+5O_2\rightarrow 3CO_2+4H_2O$

As can be seen from the balanced chemical equation:

3 moles of carbon dioxide are produced by 5 moles of oxygen.

According to avogadro's law, 1 mole of every gas occupies 22.4 L at STP.

$3\times 22.4=67.2L$ of carbon dioxide are produced by $5\times 22.4=112L$ of oxygen at STP

Thus 43.62 L of carbon dioxide are produced by =$\frac{112L}{67.2}\times 43.62=72.7L$ of oxygen at STP

Thus 72.7 liters of oxygen will produce 43.62 liters of carbon dioxide at STP.

Answer 2

The balanced chemical reaction:

C3H8 + 5O2 = 3CO2 + 4H2O

We are given the amount of the carbon dioxide to be produced. This will be the starting point of our calculations.

43.62 L CO2 ( 1 mol CO2 / 22.4 L CO2 ) (5 mol O2 / 3 mol CO2 ) ( 22.4 L O2 / 1 mol O2) = 72.7 L O2