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hjlf
2 years ago
7

Why is a solid recrystallized with the minimum of hot solvent?

Chemistry
1 answer:
VMariaS [17]2 years ago
5 0

Answer:

Recrystallization refers to the method used for purifying chemical compounds. In this method, the chemical compound along with the impurities is dissolved in an appropriate hot solvent, to separate the chemical compound and the impurity.

The pure chemical compound that separates after the recrystallization process exists in the form of crystals.

Generally, the impure chemical compound is fully dissolved in the <u>minimum amount of the solvent</u>, thus forming a saturated solution. This is because if large amount of solvent is used, then a large amount of the chemical compound will remain dissolved in the solvent, even after cooling.

<u>Therefore, all of the chemical compound will not get recrystallized.</u>

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Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
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<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

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