Question

Choose the equation below whose axis of symmetry is x = 0. (1 point) Group of answer choices y = x2 + 2x y = x2 − 16x + 58 y = x2 + 2 y = x2 − 4x + 2

Answer 1

Answer:

$(C)y = x^2 +2$

Step-by-step explanation:

Given the general form of quadratic equation $ax^2+bc+c=0$, the axis of symmetry is derived using the equation $x=-\frac{b}{2a}$

Given the equation

$y = x^2 + 2x\\a=1, b=2\\Axis of Symmetry, x=-\frac{2}{2(1)}=-1$

Next,

$y = x^2 -16x+58\\a=1, b=-16\\ Axis of Symmetry , x=-\frac{-16}{2(1)}=8$

Next,

$y = x^2 +2\\a=1, b=0\\ Axis of Symmetry , x=-\frac{0}{2(1)}=0$

Lastly,

$y = x^2 -4x+2\\a=1, b=-4\\ Axis of Symmetry , x=-\frac{-4}{2(1)}=2$

Clearly, $y = x^2 +2$ is the equation whose axis of symmetry is x=0.