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3 years ago

14

A horse stands 184 cm at the shoulder. The horse is all of the following EXCEPT ____________ tall. A) 1.84 m B) 18.4 dm C) 184,0

00 km Eliminate D) 1840 mm

1 answer:

katrin [286]3 years ago

6 0

C, 184,000 KM, as it means, "Kilometers", is a measurement of distance, close to miles.

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Samantha and Emily are pushing a box of textbooks in the same direction across their classroom. Samantha is applying a force of

velikii [3]

Answer: 20 newtons

Explanation:

Given that:

Force applied by Samantha = 10 newtons

Force applied by Emily = 10 newtons

Direction of both forces = same

Net force of their efforts = ?

Since net force of forces applied in the same direction is obtained by adding up the seperate forces applied, then

Net force = (10 newtons + 10 newtons)

Net force = 20 newtons

Thus, the net force of their efforts is 20 newtons.

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3 years ago

stich3 [128]

Answer:

In a primary cell, two electrodes (one of copper and other of zinc) of metal atoms are used. These electrodes are dipped in an electrolyte solution that causes the metals to produce their respective positive and negative ions.

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Unlike a primary cell, a dry cell contains paste of an electrolyte instead of the solution. The contents of electrolyte paste react with each other through a chemical process and convert the chemical energy into electrical energy.

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2 years ago

Why is the rock cycle really a cycle?

Naddik [55]

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3 years ago

Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Ho

lidiya [134]

Answer: $\frac{r_1}{r_2}=1.565$

Explanation:

Given

two holes are made with different sizes

Hole 1 is large in size and hole 2 is small

If the volume flow rate of water is same for both the hole then small hole must be below the large hole because for same flow rate, velocity of water is large while cross-sectional area is small so it compensate to give same flow for both the holes.

Now for radius apply Bernoulli's theorem at hole 1 and 2

$P_1+\rho gh_1=P_{atm}+\frac{1}{2}\rho v_1^2$

$P_2+\rho g6h_2=P_{atm}+\frac{1}{2}\rho v_2^2$

if hole 1 is h distance below water surface then $h_2=6h$

and $P_1=P_2=P_{atm}$

Also $v_1=\sqrt{2gh}$

$v_2=\sqrt{2g(6h)}$

and $Q=A_1v_1=A_2v_2$

$A=\pi r^2$

thus $\dfrac{r_1}{r_2}=\sqrt{\dfrac{v_2}{v_1}}$

$\dfrac{r_1}{r_2}=\sqrt{\dfrac{\sqrt{6h}}{\sqrt{h}}}$

$\frac{r_1}{r_2}=1.565$

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2 years ago

Calculate the volume of this regular solid. A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.

Kryger [21]

Answer:

The volume of the cylinder is $653.71\ \text{cm}^3$

Explanation:

Given that,

The height of the cylinder is 13 cm

Radius of the cylinder is 4 cm

We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

$V=\pi r^2 h\\\\V=\dfrac{22}{7} \times (4)^2 \times 13\\\\V=653.71\ \text{cm}^3$

So, the volume of the cylinder is $653.71\ \text{cm}^3$

4 0

2 years ago

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