Atmospheric pressure at sea level is 760 mmHg.
We have been told that at the summit the pressure is only one third the pressure at sea level.
Then the pressure at the mountain top is
![\frac{760}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B760%7D%7B3%7D%20)
mmHg
Air is made of a mixture of gases. the pressure that each gas exerts individually contributes to the total pressure of the system. The pressure that each gas exerts is the partial pressure of that gas which depends on the mole fraction of that gas or percentage composition of the individual gas.
Partial pressure of Oxygen - total pressure x percentage composition
Therefore pO₂ -
![\frac{760 * 0.21}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B760%20%2A%200.21%7D%7B3%7D%20%20)
= 53.2 mmHg
Answer is 53 mmHg
Answer:
Mass, m = 141.96 kg
Explanation:
Given that,
Moles = 5.07
Molar mass of N₂ = 28 g/mol
We need to find the mass of 5.07 mol N₂.
We know that,
No of moles is equal to mass divided by molar mass i.e.
![n=\dfrac{m}{M}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7Bm%7D%7BM%7D)
Where
m is mass of 5.07 mol of N₂
So,
![m=n\times M\\\\m=5.07\times 28\\\\m=141.96\ kg](https://tex.z-dn.net/?f=m%3Dn%5Ctimes%20M%5C%5C%5C%5Cm%3D5.07%5Ctimes%2028%5C%5C%5C%5Cm%3D141.96%5C%20kg)
So, the required mass of 5.07 mol N₂ is 141.96 kg.
Answer:
The mole fraction of hexane is 0.61
Explanation:
Raoult's law allows calculating the vapor pressure of a substance when it is forming part of an ideal solution, knowing its vapor pressure when it is pure (at the same temperature) and the composition of the ideal solution in terms of mole fraction.
Pi=xi*Pi°
where Pi is the partial pressure of component i in the solution, Pi ° is the vapor pressure of component i pure and xi is the mole fraction of component i in the liquid phase.
In a solution, once the components have reached chemical equilibrium, the total vapor pressure is:
Psolution=P1 + P2=x1*P1° +x2*P2°
In this case:
Psolution= xpentane*Ppentane° +xhexane*Phexane°
Being:
- Psolution= 258 torr
- xpentane + xhexane=1 ⇒ xpentane= 1 - xhexane
- Ppentane°= 425 torr
- xhexane= ?
- Phexane°= 151 torr
and replacing:
258 torr= (1-xhexane)* 425 torr + xhexane* 151 torr
you get:
258 torr= 425 torr - 425 torr*xhexane + xhexane* 151 torr
258 torr - 425 torr= - 425 torr*xhexane + xhexane* 151 torr
-167 torr= -274 torr*xhexane
![xhexane=\frac{-167 torr}{-274 torr}](https://tex.z-dn.net/?f=xhexane%3D%5Cfrac%7B-167%20torr%7D%7B-274%20torr%7D)
xhexane= 0.61
<u><em>The mole fraction of hexane is 0.61</em></u>
Answer:
Explanation:
No density does not change when the volume changes unless something is added to the 5 cm^3.
The answer is False