Answer:
C. 40
Explanation:
there are 40 moles of water in a 0.250 mole. use the formula to find out
40.0 = 40.0 + 0
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Answer:
1.88 × 10²³ particles
Explanation:
Given data:
Volume of H₂ = 0.7 L
Number of particles at STP = ?
Solution:
First of all we will calculate the number of moles of H₂.
PV = nRT
n = PV / RT
n = 1 atm . 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ × 273.15 K
n = 7 atm. L / 22.43 L. atm. mol⁻¹
n = 0.312 mol
it is known that,
2 g H₂ = 1 mol = 6.022 × 10²³ particles
For 0.312 mol
0.312 × 6.022 × 10²³ particles
1.88 × 10²³ particles
Answer:
Explanation:
Convert molecules to moles:
1 mole of NaNO₃= 6.02 x 10^23 molecules of NaNO₃
7.3 x10^24/(6.02 x 10^23)=12mol NaNO₃
Find molar mass:
NaNO₃=1 mole of Na and 1mole of N and 3mole of O
Find grams:
14.01g x 12= 168.12 g of N
